What two numbers add to 4 and, when multiplied together, equal −12?

2 answers:

4 0

<span>Let x = first number
Let y = second number
x + y = 4
x * y = (-12)
Solve the first equation for x.
x = 4 - y
Now substitute this value of x into the second equation.
(4 - y) * y = (-12)
4y - y² = (-12)
y² - 4y - 12 = 0
(y + 2) * (y - 6) = 0
Now set both polynomials equal to zero
y + 2 = 0
y = -2
y - 6 = 0
y = 6
If you substituted these two values for y into either equation and solve for x, you would get the combination of 6 and -2

Hope I was able to help you! :)
</span>

Fed [463]3 years ago

3 0

6 and -2. When you add -2+6, you get 4. And when you multiple -2*6 you get -12
Hope this helps!

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1/2(6 2/3+1/4)-5/24=

Helen [10]

For this case we must simplify the following expression:

$\frac {1} {2} (6 \frac {2} {3} + \frac {1} {4}) - \frac {5} {24} =$

We convert the mixed number to an improper fraction:

$6 \frac {2} {3} = \frac {3 * 6 + 2} {3} = \frac {20} {3}$

So, by rewriting we have:

$\frac {1} {2} (\frac {20} {3} + \frac {1} {4}) - \frac {5} {24} =\\\frac {1} {2} (\frac {4 * 20 + 3 * 1} {4 * 3}) - \frac {5} {24} =\\\frac {1} {2} (\frac {80 + 3} {12}) - \frac {5} {24} =\\\frac {1} {2} (\frac {83} {12}) - \frac {5} {24} =$