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Daniel [21]
2 years ago
15

Identify the independent and dependent variables in the following situation: Julie notices that her plant grows one inch for eve

ry liter of water that it receives. Question 17 options: The independent variable is the type of tap water used, and the dependent variable is the amount of water the plant receives. The independent variable is the amount of water the plant receives, and the dependent variable is the height of the plant. The independent variable is the height of the plant, and the dependent variable is the number of pieces of fruit the plant produces. The independent variable is the height of the plant, and the dependent variable is the amount of water the plant receives.
Mathematics
1 answer:
ivolga24 [154]2 years ago
4 0

Determine the independent variable and dependent variable in the situation

The independent variable is the <em><u>"</u></em><em><u>amount of water the plant receives</u></em><em><u>"</u></em>, and the dependent variable is the <u><em>"</em><em>height of the plant</em><em>"</em><em>.</em></u>

  • An independent variable is a the variable which causes a change.

  • A dependent variable is the result or effect of a change.

Therefore, the independent variable from the phenomena is <em><u>"amount of water"</u></em> and the dependent variable is the <u><em>"</em><em>height of the plant</em><em>"</em><em>.</em></u>

Read more:

brainly.com/question/23700645

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In a binomial experiment with 45 trials, the probability of more than 25 success can be approximated by What is the probability
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Complete Problem Statement:

In a binomial experiment with 45 trials, the probability of more than 25 successes can be approximated by P(Z>\frac{(25-27)}{3.29})

What is the probability of success of a single trial of this experiment?

Options:

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Step-by-step explanation:

So to solve this, we need to use the binomial distribution. When using an approximation of a binomially distributed variable through normal distribution , we get:

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by comparing with P(Z>\frac{(25-27)}{3.29}), we get:

μ=np=27

\sigma=\sqrt{np(1-p)} =3.29

put np=27

we get:

\sigma=\sqrt{27(1-p)} =3.29

take square on both sides:

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