13 divided by 1 and 3/7=9 and 1/10
$9.10
For this case , the parent function is given by [tex f (x) =x^2
[\tex]
We apply the following transformations
Vertical translations :
Suppose that k > 0
To graph y=f(x)+k, move the graph of k units upwards
For k=9
We have
[tex]h(x)=x^2+9
[\tex]
Horizontal translation
Suppose that h>0
To graph y=f(x-h) , move the graph of h units to the right
For h=4 we have :
[tex ] g (x) =(x-4) ^ 2+9
[\tex]
Answer :
The function g(x) is given by
G(x) =(x-4)2 +9
All you have to do is do the distributive property. So, for the first one you would do 5 times x which equals 5x and then you would do 5 times 4 which equals twenty. All you are left with is the addition sign. Your full equation now would be 5x+20
That would be 1 21/99 or 120/99 as an improper fraction.
