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2 years ago

PLEASE HELP ASAP!!! CORRECT ANSWERS ONLY PLEASE!!!

Mathematics

2 answers:

nataly862011 [7]2 years ago

8 0

Answer: $\bold{-\dfrac{1}{2}}$

<u>Step-by-step explanation:</u>

Average rate of change is the slope (m) between the two coordinates (-1, -1) and (1, -2).

$m=\dfrac{y_2-y_1}{x_2-x_1}$

$m = \dfrac{-2+1}{1+1}$

$=-\dfrac{1}{2}$

dezoksy [38]2 years ago

5 0

Answer:

-1/8 is the correct answer since you're actually using the points (-1, -1/4) and (1,-1/2).

Step-by-step explanation:

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Please help!! 30 points

Stels [109]

Answer:

x = 4

31x + 6 = 130

12x + 2 = 50

Step-by-step explanation:

two angles side by side are equal to 180.

(31x + 6) + (12x + 2) = 180

43x + 8 = 180

43x = 172

x = 4

31x + 6 = 124 + 4 = 130

12x + 2 = 48 + 2 = 50

8 0

3 years ago

HELP PLEASE !!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

USPshnik [31]

Answer:

65mph

Step-by-step explanation:

Add 100 and 30 together then divide by 2. You get 65 miles per hour.

7 0

3 years ago

If a population consists of 100,000,000 people and a census is taken, how many people are sampled

alex41 [277]

100,000,000 people would be the correct answer

7 0

2 years ago

Read 2 more answers

How do you work y=2x-1 <br> X=-6

Liula [17]

Multiply 2 by -6.

y=2x-1
y=2(-6)-1
y= -12-1
y= -13

4 0

3 years ago

Read 2 more answers

Set A of six numbers has a standard deviation of 3 and set B of four numbers has a standard deviation of 5. Both sets of numbers

Alenkinab [10]

Given:

$\sigma_A=3$

$n_A=6$

$\sigma_B=5$

$n_B=4$

$\overline{x}_A=\overline{x}_B$

To find:

The variance. of combined set.

Solution:

Formula for variance is

$\sigma^2=\dfrac{\sum (x_i-\overline{x})^2}{n}$ ...(i)

Using (i), we get

$\sigma_A^2=\dfrac{\sum (x_i-\overline{x}_A)^2}{n_A}$

$(3)^2=\dfrac{\sum (x_i-\overline{x}_A)^2}{6}$

$9=\dfrac{\sum (x_i-\overline{x}_A)^2}{6}$

$54=\sum (x_i-\overline{x}_A)^2$

Similarly,

$\sigma_B^2=\dfrac{\sum (x_i-\overline{x}_B)^2}{n_B}$

$(5)^2=\dfrac{\sum (x_i-\overline{x}_B)^2}{4}$

$25=\dfrac{\sum (x_i-\overline{x}_B)^2}{4}$

$100=\sum (x_i-\overline{x}_B)^2$

Now, after combining both sets, we get

$\sigma^2=\dfrac{\sum (x_i-\overline{x}_A)^2+\sum (x_i-\overline{x}_B)^2}{n_A+n_B}$

$\sigma^2=\dfrac{54+100}{6+4}$

$\sigma^2=\dfrac{154}{10}$

$\sigma^2=15.4$

Therefore, the variance of combined set is 15.4.

7 0

2 years ago