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Crazy boy [7]
3 years ago
7

Line AB contains points A (0, 1) and B (1, 5). The slope of line AB is

Mathematics
1 answer:
snow_tiger [21]3 years ago
5 0

solution is here,

slope(m)=(y2-y1)/(x2-x1)

=(5-1)/(1-0)

=4/1 =4

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in my knowledge I think 13

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Write the equation of a line that is perpendicular to -2/7x+9 that passes through the point (4, -6)
Anna11 [10]

Answer:

7y + 2x + 34 = 0

Step-by-step explanation:

The gradient for perpendicular, m = -2/7

The formular equation, y - y1 = m(x - x1)

The equation of line through (4, -6) is:

y - (-6) = -2/7(x - 4)

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3 years ago
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OlgaM077 [116]

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2 years ago
Show work how you know it’s a function or not a function for each problem. PLEASE SOMEONE HELP ME OUT
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Answer: Function, not a function, Function, not a function

Step-by-step explanation:

For it to be a function, each value of x has to map onto one value of y.

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(d) The particle moves in the positive direction when its velocity has a positive sign. You know the particle is at rest when t=0 and t=3, and because the velocity function is continuous, you need only check the sign of v(t) for values on the intervals (0, 3) and (3, 6).

We have, for instance v(1)\approx-0.91 and v(4)\approx0.91>0, which means the particle is moving the positive direction for 3, or the interval (3, 6).

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\displaystyle\int_0^6|v(t)|\,\mathrm dt=\int_0^3-v(t)\,\mathrm dt+\int_3^6v(t)\,\mathrm dt

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The total distance traveled is then 4 ft.

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