Ask question

Ask question

All categories

3 years ago

6

The runners speed per mile

2 answers:

dezoksy [38]3 years ago

8 0

Answer:10 minutes per mile

Step-by-step explanation:

antiseptic1488 [7]3 years ago

3 0

Answer:

The runner's speed is 10 minutes per mile.

Step-by-step explanation:

When looking at the graph, the first dot lands at 1.0 miles for the x-axis and 10 for the y-axis, the y-axis being in minutes. Therefore, someone can run 1.0 miles in 10 minutes.

In addition, the second dot lands on (2.0, 20), meaning he/she ran 2.0 miles in 20 minutes. Divide that by 2 and you get 1.0 miles in 10 minutes.

You might be interested in

Find an irrational number between -10 and -10.1.

Pavlova-9 [17]

Between two rational numbers there are an infinite number of irrational numbers.

Example:

$- 5 \sqrt{3} -\sqrt{2}= 5 \times 1.7320508 - 1.41421356 \approx -10.0744676\\\\
-10.1 \ \textless \ -10,0744676 \ \textless \ -10$

6 0

2 years ago

Divide mixed numbers(no decimal answers)

cestrela7 [59]

Answer:

$\\\frac{9}{10}$ NOT 100% sure! If its not this I think its $\frac{22}{45}$

8 0

2 years ago

Please help me fast!!

Lynna [10]

Y=x+70
Slope-intercept form

5 0

2 years ago

Brent's pick-up tuck can carry 1/5 ton. nina's pick-up truck can carry 500 pounds. whose pick-up truck can carry more weight? ex

Molodets [167]

Brent 1 ton is 2000 lbs /5= 400 lbs
Nina 500 lbs
So Nina 's truck can carry more

6 0

3 years ago

A solution initially contains 200 bacteria. 1. Assuming the number y increases at a rate proportional to the number present, wri

GuDViN [60]

Answer:

1. $\frac{dy}{dt}=ky$

2.543.6

Step-by-step explanation:

We are given that

y(0)=200

Let y be the number of bacteria at any time

$\frac{dy}{dt}$ =Number of bacteria per unit time

$\frac{dy}{dt}\proportional y$

$\frac{dy}{dt}=ky$

Where k=Proportionality constant

2. $\frac{dy}{y}=kdt$ ,y'(0)=100

Integrating on both sides then, we get

$lny=kt+C$

We have y(0)=200

Substitute the values then , we get

$ln 200=k(0)+C$

$C=ln 200$

Substitute the value of C then we get

$ln y=kt+ln 200$

$ln y-ln200=kt$

$ln\frac{y}{200}=kt$

$\frac{y}{200}=e^{kt}$

$y=200e^{kt}$

Differentiate w.r.t

$y'=200ke^{kt}$

Substitute the given condition then, we get

$100=200ke^{0}=200 \;because \;e^0=1$

$k=\frac{100}{200}=\frac{1}{2}$

$y=200e^{\frac{t}{2}}$

Substitute t=2

Then, we get $y=200e^{\frac{2}{2}}=200e$

$y=200(2.718)=543.6=543.6$

e=2.718

Hence, the number of bacteria after 2 hours=543.6

4 0

3 years ago