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ss7ja [257]
3 years ago
15

Express 20cm as a percentage of 3m. give your answer as a mixed number

Mathematics
1 answer:
Ludmilka [50]3 years ago
8 0

Answer:

6\frac{2}{3} %

Step-by-step explanation:

<em>First, convert 3 meters into centimeters.</em>

1m = 100cm

3m = 100 × 3 = 300cm

<em>Now, form the fraction by putting the given value, 20cm, over the total measurement, 300cm.</em>

\frac{20}{300} = \frac{2}{30} = \frac{1}{15}  ⇒ <em>Simplify your fraction to its simplest terms.</em>

<em>Next, multiply your simplified fraction by 100 to get your percentage.</em>

\frac{1}{15} × 100 = \frac{100}{15} = 6\frac{10}{15} = 6\frac{2}{3} %   ⇒ <em>Simplify your percentage to its simplest terms.</em>

<em>Hope this helped! I would really appreciate it if you would please mark me brainliest!</em>

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The temperature is changing at a constant rate of –0.75ºC per half hour. At 6:45 PM, the temperature was –4.6ºC. At what time wa
tino4ka555 [31]

Answer:

11:15PM

Step-by-step explanation:

The difference between 4.6°C and -2.1°C is 6.7

0.75×?=6.7

?=9

This is 9 half hours, which is equal to 4 1/2 hours.

Hope it helped! Please give brainliest, thank me and rate it 5 please. :)

3 0
3 years ago
Help with 30 please. thanks.​
Svet_ta [14]

Answer:

See Below.

Step-by-step explanation:

We have the equation:

\displaystyle  y = \left(3e^{2x}-4x+1\right)^{{}^1\! / \! {}_2}

And we want to show that:

\displaystyle y \frac{d^2y }{dx^2} + \left(\frac{dy}{dx}\right) ^2 = 6e^{2x}

Instead of differentiating directly, we can first square both sides:

\displaystyle y^2 = 3e^{2x} -4x + 1

We can find the first derivative through implicit differentiation:

\displaystyle 2y \frac{dy}{dx}  = 6e^{2x} -4

Hence:

\displaystyle \frac{dy}{dx} = \frac{3e^{2x} -2}{y}

And we can find the second derivative by using the quotient rule:

\displaystyle \begin{aligned}\frac{d^2y}{dx^2} & = \frac{(3e^{2x}-2)'(y)-(3e^{2x}-2)(y)'}{(y)^2}\\ \\ &= \frac{6ye^{2x}-\left(3e^{2x}-2\right)\left(\dfrac{dy}{dx}\right)}{y^2} \\ \\ &=\frac{6ye^{2x} -\left(3e^{2x} -2\right)\left(\dfrac{3e^{2x}-2}{y}\right)}{y^2}\\ \\ &=\frac{6y^2e^{2x}-\left(3e^{2x}-2\right)^2}{y^3}\end{aligned}

Substitute:

\displaystyle y\left(\frac{6y^2e^{2x}-\left(3e^{2x}-2\right)^2}{y^3}\right) + \left(\frac{3e^{2x}-2}{y}\right)^2 =6e^{2x}

Simplify:

\displaystyle \frac{6y^2e^{2x}- \left(3e^{2x} -2\right)^2}{y^2} + \frac{\left(3e^{2x}-2\right)^2}{y^2}= 6e^{2x}

Combine fractions:

\displaystyle \frac{\left(6y^2e^{2x}-\left(3e^{2x} - 2\right)^2\right) +\left(\left(3e^{2x}-2\right)^2\right)}{y^2} = 6e^{2x}

Simplify:

\displaystyle \frac{6y^2e^{2x}}{y^2} = 6e^{2x}

Simplify:

6e^{2x} \stackrel{\checkmark}{=} 6e^{2x}

Q.E.D.

6 0
3 years ago
True or false to begin an indirect proof, you assume the opposite of what you intend to prove is true
damaskus [11]

Answer:

true

Step-by-step explanation:

you must assume its false and if said statement leads to an impossibility then its proved to be true

7 0
3 years ago
Read 2 more answers
Help!!! Algebra1B
Andreyy89

Answer:

3)  y = 2

Step-by-step explanation:

Step : 1

given 2 y-1 =3

Adding '1 ' on both sides, we get

2 y -1 +1 = 3+1

2 y = 4

dividing by '2' on both sides, we get

\frac{2y}{2} = \frac{4}{2}

cancelling '2' on both sides, we get

y = 2

7 0
3 years ago
I need help on this problem.
aliya0001 [1]

In this situation, x=2.

5 0
3 years ago
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