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Tanzania [10]
3 years ago
6

Write a rule for the linear function in the graph.

Mathematics
1 answer:
Nata [24]3 years ago
4 0
Y=4x-13

that is the line
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Three friends went to the movies. Each movie ticket cost $8.50. Each person ordered a drink for $4.75. Two friends also bought p
vfiekz [6]

Answer:

P = $7.00

Step-by-step explanation:

Movie tickets = $8.50

Drink = $4.75

Two friends also bought popcorn

Total spent by the group = $53.75

Given equation:

3(8.50 + 4.75) + 2p = 53.75

Where,

P = cost of one order of popcorn

3(8.50 + 4.75) + 2p = 53.75

25.50 + 14.25 + 2p = 53.75

39.75 + 2p = 53.75

2p = 53.75 - 39.75

2p = 14

p = 14 / 2

p = 7

p = $7.00

8 0
3 years ago
A person bought some cosmetics from wholesale market at the rate of Rs 360 per dozen he sells it at Rs 80 a pair find the gain p
marusya05 [52]

Answer:

33.33%

Step-by-step explanation:

We need to calculate the <u>unit selling price and cost of each cosmetics.</u>

If a person bought some cosmetics from wholesale market at the rate of Rs 360 per dozen., then for 1 cosmetics, we will say;

x = 1 cosmetic

since 360 = 12 cosmetic

cross multiply

12x = 360

x = 360/12

x = 30

Hence the unit cost price of the cosmetics will be Rs. 30

Similarly, if he sells it at Rs 80 a pair, then he sold one cosmetic at 80/2 = Rs. 40 (a pair is 2 cosmetics)

Selling price per unit = Rs. 40

Cost price per unit = Rs. 30

percent gain = SP-CP/CP * 100%

percent gain = 40-30/30 * 100

percent gain = 10/30 * 100

percent gain = 100/3

percent gain = 33.33%

Hence the percentage gain is 33.33%

5 0
3 years ago
HHHHHHHHHHHHHHHHHHHHEEEEEEEEEEEEEEEELLLLLLLLLLLLLLLLLLPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPPP
vova2212 [387]

x²y ÷ _ = xy

x²y = xy_

x²y = x_y

x²y = xxy

x²y = x²y

Answer: x

4 0
3 years ago
A card is drawn from a deck of 52 cards. Match the correct fraction with its corresponding probability.
Molodets [167]

1. p=26/52

26/52=.5

50 percent

2. p=29/52

29/52=.56

56 percent

6 0
3 years ago
The rate of change of the number of squirrels S(t) that live on the Lehman College campus is directly proportional to 30 − S(t),
pishuonlain [190]

Answer:

S(3)=22

Step-by-step explanation:

The rate of change of the number of squirrels S(t) that live on the Lehman College campus is directly proportional to 30 − S(t).

\dfrac{dS}{dt}=k(30-S(t))\\ \dfrac{dS}{dt}+kS(t)=30k\\$The integrating factor: e^{\int k dt}=e^{kt}\\$Multiply all through by the integrating factor\\ \dfrac{dS}{dt}e^{kt}+kS(t)e^{kt}=30ke^{kt}

(Se^{kt})'=30ke^{kt} dt\\$Integrate both sides\\ Se^{kt}=\dfrac{30ke^{kt}}{k}+C$ (C a constant of integration)\\Se^{kt}=30e^{kt}+C\\$Divide both sides by e^{kt}\\S(t)=30+Ce^{-kt}

When t=0, S(t)=15

15=30+Ce^{-k*0}\\C=15-30\\C=-15

When t = 2, S(t)=20

20=30-15e^{-2k}\\20-30=-15e^{-2k}\\-10=-15e^{-2k}\\e^{-2k}=\dfrac23\\$Take the natural log of both sides$\\-2k=\ln \dfrac23\\k=-\dfrac{\ln(2/3)}{2}

Therefore:

S(t)=30-15e^{\frac{\ln(2/3)}{2}t}\\$When t=3$\\S(t)=30-15e^{\frac{\ln(2/3)}{2} \times 3}\\S(3)=21.8 \approx 22

8 0
3 years ago
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