Answer:
40th and 80th visit
the first visit where you receive both is the 40th
Step-by-step explanation:
personally, I believe that the simplest way to solve this is use an excel spreadsheet to see which visits would include both a free beverage and a free appetizer:
- both rewards would happen only twice, at the 40th and 80th visit.
you can also calculate it mathematically since multiples of 8 and 10 do not repeat themselves very much, only when 8 is multiplied by 5 and 10.
Answer:
$16
Step-by-step explanation:
1-⅗=⅖
40×⅖=16
Here's the answer
check the picture below on the top side.
we know that x = 4 = b, therefore, using the 30-60-90 rule, h = 4√3, and DC = 4+8+4 = 16.
![\bf \textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} a,b=\stackrel{bases}{parallel~sides}\\ h=height\\[-0.5em] \hrulefill\\ a=8\\ b=\stackrel{DC}{16}\\ h=4\sqrt{3} \end{cases}\implies A=\cfrac{4\sqrt{3}(8+16)}{2} \\\\\\ A=2\sqrt{3}(24)\implies \boxed{A=48\sqrt{3}}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Barea%20of%20a%20trapezoid%7D%5C%5C%5C%5C%0AA%3D%5Ccfrac%7Bh%28a%2Bb%29%7D%7B2%7D~~%0A%5Cbegin%7Bcases%7D%0Aa%2Cb%3D%5Cstackrel%7Bbases%7D%7Bparallel~sides%7D%5C%5C%0Ah%3Dheight%5C%5C%5B-0.5em%5D%0A%5Chrulefill%5C%5C%0Aa%3D8%5C%5C%0Ab%3D%5Cstackrel%7BDC%7D%7B16%7D%5C%5C%0Ah%3D4%5Csqrt%7B3%7D%0A%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Ccfrac%7B4%5Csqrt%7B3%7D%288%2B16%29%7D%7B2%7D%0A%5C%5C%5C%5C%5C%5C%0AA%3D2%5Csqrt%7B3%7D%2824%29%5Cimplies%20%5Cboxed%7BA%3D48%5Csqrt%7B3%7D%7D)
now, check the picture below on the bottom side.
since we know x = 9, then b = 9, therefore DC = 9+6+9 = 24, and h = b = 9.
![\bf \textit{area of a trapezoid}\\\\ A=\cfrac{h(a+b)}{2}~~ \begin{cases} a,b=\stackrel{bases}{parallel~sides}\\ h=height\\[-0.5em] \hrulefill\\ a=6\\ b=\stackrel{DC}{24}\\ h=9 \end{cases}\implies A=\cfrac{9(6+24)}{2} \\\\\\ A=\cfrac{9(30)}{2}\implies \boxed{A=135}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Barea%20of%20a%20trapezoid%7D%5C%5C%5C%5C%0AA%3D%5Ccfrac%7Bh%28a%2Bb%29%7D%7B2%7D~~%0A%5Cbegin%7Bcases%7D%0Aa%2Cb%3D%5Cstackrel%7Bbases%7D%7Bparallel~sides%7D%5C%5C%0Ah%3Dheight%5C%5C%5B-0.5em%5D%0A%5Chrulefill%5C%5C%0Aa%3D6%5C%5C%0Ab%3D%5Cstackrel%7BDC%7D%7B24%7D%5C%5C%0Ah%3D9%0A%5Cend%7Bcases%7D%5Cimplies%20A%3D%5Ccfrac%7B9%286%2B24%29%7D%7B2%7D%0A%5C%5C%5C%5C%5C%5C%0AA%3D%5Ccfrac%7B9%2830%29%7D%7B2%7D%5Cimplies%20%5Cboxed%7BA%3D135%7D)
Answer:
The answer is explained below
Step-by-step explanation:
Given that The volume of air inside a rubber ball with radius r can be found using the function V(r) = 
, this means that the volume of the air inside the rubber ball is a function of the radius of the rubber ball, that is as the radius of the rubber ball changes, also the volume of the ball changes.
As seen from the function, the radius is directly proportional to the volume of the ball, if the radius increases, the volume also increases.
is equal to the volume of the ball when the radius of the ball is 
. Therefore:
Answer:
Step-by-step explanation:
14000 after 5 years
