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11Alexandr11 [23.1K]
2 years ago
12

A car completes a journey in 12 hours at an average speed of 52 km/h.

Mathematics
1 answer:
yawa3891 [41]2 years ago
8 0

Answer:

use the formula speed=distance/time

distance=speed×time

and time = distance/speed

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In one year, a bird farm sold 375 total chickens. of these, there were 37 more Cornish hens than turkeys. How many Cornish hens
GarryVolchara [31]

Answer:

206 Cornish hens

169 turkeys

Step-by-step explanation:

Let c represent the number of Cornish hens sold. Then c-37 is the number of turkeys sold. The total sales would be ...

... c + (c-37) = 375

... 2c = 412 . . . . collect terms, add 37

... c = 206 . . . . Cornish hens sold

... (c-37) = 169 . . . turkeys sold

_____

<em>Comment on this type of problem</em>

Note that the solution to this problem is that the larger number (number of cornish hens) is half the sum of the total and the difference: (375+37)/2 = 206. This is the general solution for this type of "sum and difference" problem.

The larger contributor is half the total plus half the difference; the smaller contributor is half the total minus half the difference.

Cornish hens = (1/2)(375 +37) = 206

Turkeys = (1/2)(375 -37) = 169

3 0
3 years ago
1+10=10 2+20=20 3+30=28 4+40=32 5+50=?​
Vlad1618 [11]

Answer:

<em>Well, Here's your answer 1+10=11, 2+20=22, 3+30=33, 4+40=44, and 5+50=55. Hope That Helps!</em>

<em>From Itsbrazts.</em>

3 0
3 years ago
Read 2 more answers
The length of a rectangle is 3 times its width. The perimeter is 39. Find the length and width of the rectangle.​
nata0808 [166]

Answer:

Let width of rectangle be x cm.

3x+x+3x+x=39

8x=39

x=39÷8

=39/8

=4/7/8

3x=39/8×3

=117/8

=14/5/8

Hence, length=14/5/8cm while width=4/7/8cm.

6 0
3 years ago
Two faces of a six-sided die are painted red, two are painted blue, and two are painted yellow. The die is rolled three times, a
Keith_Richards [23]

Answer:

(a) 4/9

(b) 19/27

Step-by-step explanation:

The probability of each die turning up red or not turning red are:

P(R) =\frac{2}{6}= \frac{1}{3}\\P(O) =\frac{4}{6}= \frac{2}{3}

(a). Exactly one face up is red.

The odds of only the first die being red are:

P(A=R) =\frac{1}{3} *\frac{2}{3}* \frac{2}{3} \\P(1=R) =\frac{4}{27}

The same odds are valid for only the second or only the third die being red. Therefore, the probability that exactly one die turns up red is:

P(R=1) = 3*\frac{4}{27}\\P(R=1) = \frac{4}{9}

(b). At least one face up is red.

The probability that at least one die turns up red is the sum of the probabilities of exactly one (found in the previous item), two or all dice turning up red.

Following the same logic as in the previous item, the probability that exactly two dice turn up red is:

P(R=2) = 3*(\frac{1}{3}*\frac{1}{3}*\frac{2}{3})\\P(R=2) = \frac{2}{9}

The probability that all die turn up red is:

P(R=3) = \frac{1}{3}*\frac{1}{3}*\frac{1}{3}\\P(R=3)=\frac{1}{27}

Thus, the probability that at least one die turns up red is:

P= P(R=1)+P(R=2)+P(R=3) = \frac{4}{9}+\frac{2}{9}+\frac{1}{27}\\P=\frac{19}{27}

4 0
3 years ago
Mark all of the statements that are true.
aksik [14]
C.,E
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4 0
3 years ago
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