an Integer is a while positive or negative number. so your integer would be 43
Answer:
-6.5 would be your answer
Step-by-step explanation:
T = 5, so after 5 years
p(t) = t^3 - 14t^2 + 20t + 120
Take derivative to find minimum:
p’(t) = 3t^2 - 28t + 10
Factor to solve for t:
p’(t) = (3t - 2)(t - 5)
0 = (3t - 2)(t - 5)
0 = 3t - 2
2 = 3t
2/3 = t
Plug 2/3 into original equation, this is a maximum. We want the minimum:
0 = t - 5
5 = t
Plug back into original:
5^3 - 14(5)^2 + 20(5) + 120
125 - 14(25) + 100 + 120
125 - 350 + 220
- 225 + 220
p(5) = -5
1/3 times 6/8
1/3 times 3/4
So, the answer is 3/12
Simplify: 1/4
Answer:
(D) Divide the first equation,
, by 2.
Step-by-step explanation:
Given:

We need to find the operation performed on equation so as to get resultant equation as:


From Above we can see that there is no change in equation 2 with respect to resultant equation.
Also Resultant equation is simplified form of equation 1.
Simplifying equation 1 we get;

We can see that 2 is the common multiple on both side.
Hence we will divide equation 1 with 2 we get

which is the resultant equation.
Hence (D) Divide the first equation,
, by 2 is the correct option.