Recall that the general equation for a line is y=mx+b where m is the slope and b is the y-intercept.
First, let's find the slope by finding
(y2-y1)/(x2-x1):
(-8-0)/(-5-3)
-8/-8
1
Now we know the equation is y=1x+b, or y=x+b.
By plugging in one of the two points we know is on the line, we can solve for b.
0=3+b
b=-3
So the equation is:
y=x-3
Can’t help with that sorry
Answer:
f(x) = |x|
g(x) = |x| - 2
h(x) = |x| + 3
Step-by-step explanation:
All the functions graphed represent the absolute value functions.
Since function g(x) passes through (0, 0) and (1, 1),
Let the equation of a line passing through these points is,
y = mx + b
Slope of the line passing through these points 'm' = 
m = 1
y-intercept of the line 'b' = 0
Therefore, equation of the line will be,
y = x
And the function representing the two lines (both are the mirror images) joining at the origin will be,
f(x) = |x|
When the parent function is shifted 3 units up, the new function will be
h(x) = |x| + 3
When the parent function is shifted 2 units down,
g(x) = |x| - 2
Answer:
The radius of the circle is 9 units.
Step-by-step explanation:
To calculate the area of the circle we need to find it's radius, since we have the area of the sector and it's angle, therefore we can calculate the radius by using the following formula:
sector area = (central angle)*pi*r²/360
27pi = 120*pi*r²/360
27pi = pi*r²/3
27 = r²/3
r² = 81
r = sqrt(81) = 9
The radius of the circle is 9 units.