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3 years ago

Compare the structure of silicon oxide and Diamond and describe their physically properties in terms of These structure

Chemistry

1 answer:

Iteru [2.4K]3 years ago

6 0

Answer:

Here's what I get

Explanation:

Both diamond and SiO₂ are network solids. Their atoms are all joined together so a crystal of either diamond or SO₂is one giant molecule.

Structure

In diamond, each C atom is covalently attached to four other C atoms.

The structure of SiO₂ is like that of diamond. The difference is that there is an O atom between each atom of Si.

Properties

Both substances are

High-melting
Hard
Insoluble in both polar and nonpolar solvents
Poor conductors of electricity

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The surface area of an object to be gold plated is 49.8 cm2 and the density of gold is 19.3 g/cm-3. A current of 3.15. A is appl

garik1379 [7]

Answer: Time required to deposit an even layer of gold with given thickness is $5.3 \times 10^{2}$ sec.

Explanation:

The given data is as follows.

Surface area = 49.8 $cm^{2}$ ,

Density of gold = 19.3 $g/cm^{3}$ ,

Current = 3.15 A, thickness of gold layer = $1.2 \times 10^{-3} cm$

It is known that relation between volume, area and thickness is as follows.

V = Surface area × Thickness

= $49.8 \times 1.2 \times 10^{-3} cm$

= 0.05988 $cm^{3}$

Therefore, we will calculate the time required to deposit an even layer of gold with given thickness is calculated as follows.

$0.05988 \times cm^{3} \times \frac{19.3 g Au}{1 cm^{3}} \times \frac{1 mol Au}{197 g Au} \times \frac{3 mol e^{-}}{1 mol Au} \times \frac{96485}{1 mol e^{-}} \times \frac{1 As}{1 C} \times \frac{1}{3.20 A}$

= $5.3 \times 10^{2}$ sec

Thus, we can conclude that time required to deposit an even layer of gold with given thickness is $5.3 \times 10^{2}$ sec.

4 0

3 years ago

Which event occurs after erosion of Earth's surface?

masya89 [10]

Answer: Surface materials breaks down into smaller pieces.

Explanation:

Erosion is the geological process in which the topmost layer of the soil is worn away and transported by natural forces such as wind or water. A process which resembles erosion is weathering, which lead to breaking down or dissolution of rocks, but does not involve movement of the rock or soil materials.

After erosion the layers at the top of the soil are also broken down to smaller bits by factors such as water and winds.

4 0

3 years ago

Read 2 more answers

enot [183]

Could you add a screenshot so we know what's being asked please?

5 0

3 years ago

In the following reaction HF(aq) + HPO42-(aq) = F-(aq) + H2PO4-(aq)

garik1379 [7]

Answer:

Explanation:

HF gives its H to HPO42 making it H2PO4, so HF is the acid and F- is the conj base

6 0

3 years ago

A 1.67-g sample of solid silver reacted in excess chlorine gas to give a2.21-g sample of pure solid Agcl.The heat given off in t

kotegsom [21]

Given:

Mass of Ag = 1.67 g

Mass of Cl = 2.21 g

Heat evolved = 1.96 kJ

To determine:

The enthalpy of formation of AgCl(s)

Explanation:

The reaction is:

2Ag(s) + Cl2(g) → 2AgCl(s)

Calculate the moles of Ag and Cl from the given masses

Atomic mass of Ag = 108 g/mol

# moles of Ag = 1.67/108 = 0.0155 moles

Atomic mass of Cl = 35 g/mol

# moles of Cl = 2.21/35 = 0.0631 moles

Since moles of Ag << moles of Cl, silver is the limiting reagent.

Based on reaction stoichiometry: # moles of AgCl formed = 0.0155 moles

Enthalpy of formation of AgCl = 1.96 kJ/0.0155 moles = 126.5 kJ/mol

Ans: Formation enthalpy = 126.5 kJ/mol

6 0

3 years ago

Read 2 more answers

Compare the structure of silicon oxide and Diamond and describe their physically properties in terms of These structure ​

Compare the structure of silicon oxide and Diamond and describe their physically properties in terms of These structure