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3 years ago

What is a hydrogen bond?

1 answer:

3 0

Explanation: Hydrogen bonds are the strongest one of the intermolecular forces. A hydrogen bond is a bond between hydrogen in one molecule or the other ones are fluorine and nitrogen. So it's between a hydrogen in one molecule and an electronegative atom in another molecule. So they always involve hydrogen.

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Which statement explains how the charges on objects determine the electric force between them?(1 point)

lubasha [3.4K]

Answer:

Objects with the same charge repel each other, and objects with opposite charges attract each other.

Explanation:

The Coulomb law states that opposite charges attract each other and like charges repel each other. That means two positive charges repel each other but a positive and a negative charge attract.

8 0

2 years ago

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How many electrons would be exchanged from lithium and fluorine

Vikki [24]

Fluorine - Seven electrons of it's own.

Lithium would give up one electron, so there for, fluorine is then left with eight.

3 0

3 years ago

The more impressive the tail of a male peacock, the higher its chances of finding a mate. Female peacocks choose mates based on

Kipish [7]

C i took the test and got it correct

5 0

2 years ago

Write the oxidation and reduction half reactions;

luda_lava [24]

Answer:

$Fe^{2+}$ ⇒ $Fe^{3+}+e^-$

$Br_2+2e^-$ ⇒ $2Br^-$

$Mg$ ⇒ $Mg^{2+}+2e^-$

$Cr^{3+}+e^-$ ⇒ $Cr^{3+}$

Explanation:

Remember that positive number superscripts mean electrons lack and negative numbers mean electrons 'excess' (if we compare it with the neutral element). So, for the case of Fe2+ which is converted to Fe3+, we know that in Fe2+ there is a two electrons lack, while in Fe3+ there is a 3 electrons lack; it means that Fe2+ was converted to Fe3+ but releasing one electron:

$Fe^{2+}$ ⇒ $Fe^{3+}+e^-$

The same analysis is applied to Br2; Br2 is a molecule which is said to have a zero superscript because it is an apolar covalent bond; and it is converted to Br-, which, according to what I wrote above, means that there is a one electron excess. So, Br2 must have received an electron in order to change to Br-; but Br2 can't change to Br- as simple as that because Br2 is a molecule, not an atom; it is a molecule that has two Br atoms, so, Br2 must give two Br- ions as products, but receiving one electron for each one:

$Br_2+2e^-$ ⇒ $2Br^-$

Applying the same, in Mg2+ there is a 2 electrons lack, and in Mg is not electron lack (its superscript is zero), so Mg must have released two electrons in order to change to Mg2+:

$Mg$ ⇒ $Mg^{2+}+2e^-$

Cr3+ has a 3 electrons lack, and Cr2+ a two electrons one, so, Cr3+ must receive an electron to convert to Cr2+:

$Cr^{3+}+e^-$ ⇒ $Cr^{3+}$

3 0

4 years ago

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Which of the following pairs of atoms would exhibit ionic bonding?

LekaFEV [45]

Its strontium and oxygen.

3 0

3 years ago

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