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4 years ago

Write the following equation in standard form. y=-2x-7

Mathematics

1 answer:

frosja888 [35]4 years ago

5 0

Answer:

2x+y=−7

Step-by-step explanation:

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The velocity v of an object rolled down an inclined plane is given by the formula v=39d where d is the distance the object has r

Nadya [2.5K]

V = 39d

Make d the subject

d = v/39

4 0

3 years ago

If you bought your car 5 years ago for $15,000 and today you can sell for $7000, what was it's rate of depreciation? Round to tw

serg [7]

Answer : The rate of depreciation is, $16000

Step-by-step explanation :

Formula used to calculate the rate of depreciation is:

$\text{Depreciation rate}=\frac{\text{Purchase price of asset }+\text{ Salvage value}}{\text{Estimate life of asset}}$

Given:

Purchase price of asset = $15000

Salvage value = $7000

Estimate life asset = 3 years

Now put all the given values in the above formula, we get:

$\text{Depreciation rate}=\frac{15000+7000}{5}$

Deprecation rate = $16000

Therefore, the rate of depreciation is, $16000

5 0

3 years ago

Suppose that the Celsius temperature at the point (x, y) in the xy-plane is T(x, y) = x sin 2y and that distance in the xy-plane

liraira [26]

Missing information:

How fast is the temperature experienced by the particle changing in degrees Celsius per meter at the point

$P = (\frac{1}{2}, \frac{\sqrt 3}{2})$

Answer:

$Rate = 0.935042^\circ /cm$

Step-by-step explanation:

Given

$P = (\frac{1}{2}, \frac{\sqrt 3}{2})$

$T(x,y) =x\sin2y$

$r = 1m$

$v = 2m/s$

Express the given point P as a unit tangent vector:

$P = (\frac{1}{2}, \frac{\sqrt 3}{2})$

$u = \frac{\sqrt 3}{2}i - \frac{1}{2}j$

Next, find the gradient of P and T using: $\triangle T = \nabla T * u$

Where

$\nabla T|_{(\frac{1}{2}, \frac{\sqrt 3}{2})} = (sin \sqrt 3)i + (cos \sqrt 3)j$

So: the gradient becomes:

$\triangle T = \nabla T * u$

$\triangle T = [(sin \sqrt 3)i + (cos \sqrt 3)j] * [\frac{\sqrt 3}{2}i - \frac{1}{2}j]$

By vector multiplication, we have:

$\triangle T = (sin \sqrt 3)* \frac{\sqrt 3}{2} - (cos \sqrt 3) \frac{1}{2}$

$\triangle T = 0.9870 * 0.8660 - (-0.1606 * 0.5)$

$\triangle T = 0.9870 * 0.8660 +0.1606 * 0.5$

$\triangle T = 0.935042$

Hence, the rate is:

$Rate = \triangle T = 0.935042^\circ /cm$

3 0

3 years ago

In a rectangle ABCD if AB=4x and DC=7x-9,find the length of AB.(Lengths are in cm).

myrzilka [38]

Answer:

12 cm

Step-by-step explanation:

AB and DC are parallel to each other, so they are the same length. Set their lengths equal to each other and solve for x

4x = 7x - 9

4x - 7x = 7x - 7x -9

-3x = -9

-3x/-3 = -9/-3

x = 3

Now solve for AB.

AB = 4x

AB = 4(3)

AB = 12

8 0

2 years ago

Here you go this is the full question please help

hammer [34]

I don’t see anything is there supposed to be a picture or?

8 0

3 years ago

Read 2 more answers