What is the rule for finding the distance of a point when the points are in the same Quadrant?
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Answer:
The 95% confidence interval for the population's mean length of vacation, in days, is (4.24, 4.76).
The 92% confidence interval for the population's mean length of vacation, in days, is (4.27, 4.73).
Step-by-step explanation:
We have the standard deviations for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 85 - 1 = 84
95% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 84 degrees of freedom(y-axis) and a confidence level of . So we have T = 1.989.
The margin of error is:
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 4.5 - 0.26 = 4.24 days
The upper end of the interval is the sample mean added to M. So it is 4.5 + 0.26 = 4.76 days
The 95% confidence interval for the population's mean length of vacation, in days, is (4.24, 4.76).
92% confidence interval:
Following the sample logic, the critical value is 1.772. So
The lower end of the interval is the sample mean subtracted by M. So it is 4.5 - 0.23 = 4.27 days
The upper end of the interval is the sample mean added to M. So it is 4.5 + 0.23 = 4.73 days
The 92% confidence interval for the population's mean length of vacation, in days, is (4.27, 4.73).
Answer:
367600km
Step-By-Step Explanation
Planets, moon and satellites follow elliptic orbits..
- The eccentricity 0≤e<1 describes the shape of the ellipse where an eccentricity of zero is a perfect circle.
- The furthest distance of the Moon from the Earth in its orbit is called the Apogee.
- The closest distance of the Moon from the Earth in its orbit is called the Perigee.
The Apogee (A), and Perigee(P) is related to the semi-major axis(a) of the ellipse and its eccentricity by the equations:
A=a(1+e) ……(1)
P=a(1−e) ……(2)
The closest distance Perigee, P=363 300 km
Eccentricity, e = 0.0059.
From Equation 2,
Using a=365456.19km in Equation (1)
The furthest distance,