Answer:
Not equivalent
Step-by-step explanation:
The three would also be distributed to z making the correct equivalent expression 15+3z
By using the known relations for similar triangles, we will see that the height of the basketball hoop is H = 113 ft.
<h3>
How to find the height of the basketball hoop?</h3>
In this situation, you and your shadow make a similar triangle to the one that makes the basketball hoop and its shadow.
This would mean that the quotients between the sides must be the same, so:
The <em>quotient between your height and your shadow's length must be the same as the quotient between the hoop's height and its shadow's length.</em>
- Your height is 68 in
- Your shadow is 62 in long.
You are at 41 in from the pole, and your shadow coincides with the shadow of the pole, so the length of the pole's shadow is:
41in + 62in = 103 in
And we define H as the height of the basketball hoop.
So we have that:
H/103in = 68in/62in
H = (68in/62in)*103in = 112.97 in
Rounding to the nearest foot, the height is 113ft.
If you want to learn more about triangles, you can read:
brainly.com/question/14285697
Answer:
![V = \frac{182.4 mi}{3 hr}= 60.8 \frac{mi}{hr}](https://tex.z-dn.net/?f=%20V%20%3D%20%5Cfrac%7B182.4%20mi%7D%7B3%20hr%7D%3D%2060.8%20%5Cfrac%7Bmi%7D%7Bhr%7D)
And then we can find the distance travelled in 11 hours with this formula:
![D = Vt](https://tex.z-dn.net/?f=%20D%20%3D%20Vt)
And replacing we got:
![D = 60.8 \frac{mi}{hr} *11 hr =668.8 mi](https://tex.z-dn.net/?f=%20D%20%3D%2060.8%20%5Cfrac%7Bmi%7D%7Bhr%7D%20%2A11%20hr%20%3D668.8%20mi)
So then after 11 hours she will travel 668.8 mi
Step-by-step explanation:
For this case w eknow that Alicia drove at a constant speed 182.4 mi in 3 hours. We can find the speed with this formula:
![V= \frac{D}{t}](https://tex.z-dn.net/?f=%20V%3D%20%5Cfrac%7BD%7D%7Bt%7D)
Where V is the velocity, D the distance and t the time if we replace we got:
![V = \frac{182.4 mi}{3 hr}= 60.8 \frac{mi}{hr}](https://tex.z-dn.net/?f=%20V%20%3D%20%5Cfrac%7B182.4%20mi%7D%7B3%20hr%7D%3D%2060.8%20%5Cfrac%7Bmi%7D%7Bhr%7D)
And then we can find the distance travelled in 11 hours with this formula:
![D = Vt](https://tex.z-dn.net/?f=%20D%20%3D%20Vt)
And replacing we got:
![D = 60.8 \frac{mi}{hr} *11 hr =668.8 mi](https://tex.z-dn.net/?f=%20D%20%3D%2060.8%20%5Cfrac%7Bmi%7D%7Bhr%7D%20%2A11%20hr%20%3D668.8%20mi)
So then after 11 hours she will travel 668.8 mi
Answer:
C
Step-by-step explanation: The standard form of an exponential equation is
![a^{x+h} +k](https://tex.z-dn.net/?f=a%5E%7Bx%2Bh%7D%20%2Bk)
where a is the vertical dilation, h is the horinzontial translation, and k is the vertical translation.
Lets go through these options step by step.
A. In an exponetial equation, when k>1, the graph is translated upwards vertically. However, k could still be positive and doesn't be the shape of the picture of the graph always.
Plus our exponential function has an horinzontial asymptote at y=-4 so k here is negative, not positive.
B. When a<0, the graph end behavior changes. When a>1, the right side of the graph approaches infinity while the left side approaches an asymptote. However, when a<0, the graph could be two things. One ( when a< -1) could be that the right side approaches negative infinity, and the left side approaches asymptote. The other could be that (when -1<a<0) that the right side approaches an asymptote and the left side approaches negative infinity. In this function, this models a traditional exponetial function, when a is greater than 1 so B/D is Wrong.
C is correct, when a>1, the end behavior for the right side is infinity, and for the left side is some asymptote.