1. Write your own word problem and share it with the group.
1 answer:
The solution of the word problem is a = 2
Word Problems are mathematical problems presented in complete languages, rather than in mathematical notations.
Example: Let a number is divided by half, the result is added to itself to give 6, what is the number?
Solution: Let the number be a
Now, dividing a by half, we get
a ÷ = 2a
Now, adding the result to the number itself, we will get 6 i.e.,
2a + a = 6
3a = 6
Dividing both the sides by 3, we get
a = 2
Therefore, the solution is a = 2
Complete question: Write your own word problem and share it with the group. Then translate your problem into its resulting math equation. What steps would you then follow to solve for the variable?
Know more about Word Problems: -brainly.com/question/21405634
#SPJ9
You might be interested in
Answer:
To this question; we want to show that if two antipodal points on a sphere were A and B, for any random point C on the sphere, AC is perpendicular to BC?
Step-by-step explanation:
I would proceed by imagining the sphere in a three dimensional Cartesian coordinate system. For example, use a sphere of diameter 2 and let it sit at the origin. Then (0, 0, 1) and (0, 0, -1) are the vector locations of the “north and south poles” of the sphere.
Now choose the vector location of any point on the surface of the sphere. It will have a vector location - we’ll call it (x, y, z). Now the vectors from your point to the two poles are (-x, -y, 1-z) and (-x, -y, -1-z).
Now just form the dot product of those two vectors:
(-x, -y, 1-z) . (-x, -y, -1-z) = x^2 +y^2 + (1-z)*(-1-z)
Now the truth of your claim will be embodied in that dot product being zero:
x^2 + y^2 - (1+z)(1-z) = 0
x^2 + y^2 - (1-z^2) = 0
x^2 + y^2 + z^2 = 1
But that last line is just the definition of points on the surface of a sphere of radius 1, so the claim is proven.
Since R>0 and AC is perpendicular to BC, the <ACB is at right angle.
Please, find attached a simple image to show antipodal points (Two points that makes a diameter) and a point C on the sphere.
