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creativ13 [48]
1 year ago
5

1. Write your own word problem and share it with the group.

Mathematics
1 answer:
Yuki888 [10]1 year ago
3 0

The solution of the word problem is a = 2

Word Problems are mathematical problems presented in complete languages, rather than in mathematical notations.

Example: Let a number is divided by half, the result is added to itself to give 6, what is the number?

Solution: Let the number be a

Now, dividing a by half, we get

a ÷ \frac{1}{2} = 2a

Now, adding the result to the number itself, we will get 6 i.e.,

2a + a = 6

3a = 6

Dividing both the sides by 3, we get

a = 2

Therefore, the solution is a = 2

Complete question: Write your own word problem and share it with the group. Then translate your problem into its resulting math equation. What steps would you then follow to solve for the variable?

Know more about Word Problems: -brainly.com/question/21405634

#SPJ9

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Please help with this question ​
zalisa [80]

Answer:

4cm^2

Step-by-step explanation:

First we need to find the length of the height of the triangle using Pythagoras:

a^2+b^2=c^2 (Substitute in what we have)

a^2+3√2(^2)=2√5(^2)   =   a^2 + 18 = 20 -> 20-18=2 √2=BD

Now we can find the area:

AD+DC= 3√2 + √2 = 4√2 x √2 = 8/2 = 4

6 0
3 years ago
Need help with this
stira [4]

Answer: 5,356 is the right asnwer

Step-by-step explanation: I did the paper hope this helps :)

6 0
3 years ago
Is 3.774447444744474447444 a rational number
jarptica [38.1K]
No it is an irrational number because it is a decimal with repeating numbers.
6 0
3 years ago
Ana escribe conjuntos de cinco enteros positivos consecutivos con la siguiente propiedad: La suma de tres de los números es tan
Keith_Richards [23]

Answer:

a) 1.

Step-by-step explanation:

Supongamos que el primer número entero positivo es a tal que a ∈ Z⁺.

Luego, el conjunto de los cinco enteros positivos se puede expresar como

A = {a; a+1; a+2; a+3; a+4}

Dada la condición del problema, se debe cumplir que

a + (a+1) + (a+2) = (a+3) + (a+4)

⇒  3a + 3 = 2a + 7

Resolviendo la ecuación resulta

a = 4

Luego, el conjunto A nos resulta

A = {4; 5; 6; 7; 8}

Puede concluirse que sólo un conjunto cumple con esta condición.

5 0
3 years ago
Find the least common multiple of 3,4,5,6,10,15
Reika [66]
The least common multiple for 3, 4, 5, 6, 10, and 15 is 60. 
8 0
3 years ago
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