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3 years ago

IMANU PAYS 30 EACH MONTH FOR HIS GYM MEMBERSHIP WHAT IS THE CHANGE IN THE AMOUNT OF MONEY IN HIS ACCOUNT AFTER 2/3 OF YEAR

Mathematics

1 answer:

likoan [24]3 years ago

4 0

240 is the answer to your question

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Sonia makes and sells jewelry she got an order for 12 gold rings each ring weighs 2.3 grams how much gold does she need?

Shalnov [3]

If each ring weighs 2.3 grams, the answer is 2.3*12 or 27.6 grams. This is because there are 12 rings of 2.3 grams each.

4 0

4 years ago

What will be the result of substituting 2 for x in both expressions below? One-half x + 4 x + 6 minus one-half x minus 2 Both ex

Anit [1.1K]

Answer:

Both expressions equal 5 when substituting 2 for x because both expressions are equivalent

Step-by-step explanation:

Given

$\frac{1}{2}x + 4$ - Expression 1

$x + 6 - \frac{1}{2}x - 2$ -- - Expression 2

Required

Find the result of both expressions when $x = 2$

<em>Expression 1</em>

$\frac{1}{2}x + 4$

Substitute $x = 2$

$\frac{1}{2} * 2 + 4$

$1 + 4$

$Result = 5$

<em>Expression 2</em>

$x + 6 - \frac{1}{2}x - 2$

Substitute $x = 2$

$2 + 6 - \frac{1}{2} * 2 - 2$

$2 + 6 -1 -2$

$Result = 5$

7 0

3 years ago

Read 2 more answers

MARK BRAINLIEST

Harrizon [31]

Answer:

263,267

Step-by-step explanation:

473/2 is 263.5 and so just add .5 to one and subtract .5 from the other

3 0

3 years ago

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The equation of a parabola is y=1/8x2−4x+41 .

Dafna1 [17]

Y=7............................................................................................................................................................

3 0

3 years ago

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Select the correct expressions. 1 Identify each expression that represents the slope of a tangent to the curve y= * +1 at any po

Olegator [25]

The expressions which represents the slope of a tangent to the curve $y=\frac{1}{x+1}$ at any point (x, y) are:

$f'(x) =limh \rightarrow 0\frac{-h}{h(x+1)(x+h+1)}\\\\f'(x) =limh \rightarrow 0\frac{-h}{x^2h+2xh+xh^2+h^2 +1}$

<h3>The slope of a tangent to the curve.</h3>

Mathematically, the slope of a tangent line to the curve is given by this equation:

$f'(x) =limh \rightarrow 0\frac{f(x+h)-f(x)}{h}$

Given the function:

$f(x)=y=\frac{1}{x+1}$

When (x + h), we have:

$f(x+h)=y=\frac{1}{x+h+1}$

Next, we would find the derivative of f(x):

$f'(x) =limh \rightarrow 0\frac{\frac{1}{x+h+1} -\frac{1}{x+1}}{h}\\\\f'(x) =limh \rightarrow 0\frac{x+1 -(x+h+1)}{h(x+1)(x+h+1)}\\\\f'(x) =limh \rightarrow 0\frac{x+1 -x-h-1}{h(x+1)(x+h+1)}\\\\f'(x) =limh \rightarrow 0\frac{-h}{h(x+1)(x+h+1)}\\\\f'(x) =limh \rightarrow 0\frac{-h}{x^2h+2xh+xh^2+h^2 +1}\\\\f'(x) = \frac{-1}{(x+1)(x+1)} \\\\f'(x) = \frac{-1}{(x+1)^2}$

Read more on slope of a tangent here: brainly.com/question/26015157

#SPJ1

5 0

3 years ago