A. Not a function since we have the points (-1,0) and (-1,3). The x value repeats while the y values are different. Plugging in x = -1 leads to multiple outputs, which shows we don't have a function. To get a better visual, you can plot the points. You'll see that the points form a vertical line. Therefore, this graph fails the vertical line test.
B. This is a function. All of the x values are different. The points, when graphed, pass the vertical line test. In other words, its impossible to draw a vertical line through any two points on the graph. Any x input here leads to exactly one y output.
C. This is not a function. Like choice A, we have repeated x values. In this case we have (4,6) and (4,7). The x value x = 4 repeats itself leading to multiple outputs y = 6 and y = 7
D. This is also not a function. The x value x = 0 repeats itself. The graph fails the vertical line test.
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Answer: Choice B
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Answer:
The value of ROE that will be exceeded by 78% of the firms is -1.77%.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean 
and standard deviation 
the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
The mean ROE for the firms studied was 14.93% and the standard deviation was 21.74%. This means that 
What value of ROE will be exceeded by 78% of the firms?
This is the value of X when Z has a pvalue of 1-0.78 = 0.22.
This is 
So:
The value of ROE that will be exceeded by 78% of the firms is -1.77%.
Here is my answer, hope to help you
Answer:
Point Form:
(
−
2
,
−
2
)
Equation Form:
x
= −
2
, y
= −
2
Step-by-step explanation:
Solve for the first variable in one of the equations, then substitute the result into the other equation.
Answer: The smallest valuest value for<em> k </em>is 10, such that LCM o<em>f k</em> and 6 is 60.
Step-by-step explanation:
We know that, LCM = Least common multiple.
For example : LACM of 12 and 60 is 60.
If LCM of k and 6 is 60.
i.e. the least common multiple of k and 6 is 60.
Since, 10 x 6 = 60.
The smallest valuest value for<em> k </em>should be 10, such that LCM o<em>f k</em> and 6 is 60.
Hence, the smallest value of k is 10.
