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3 years ago

I need help with this what’s the answer

Mathematics

2 answers:

Lostsunrise [7]3 years ago

7 0

Answer:

x+4

Step-by-step explanation:

To solve this question we must look at the examples :

x=2 and y=6

6-2=4

x=2 and y=7

7-3=4

so the aswer is : y = x + 4

matrenka [14]3 years ago

3 0

Answer:

If we look at the table we notice that 2 + 4 = 6, 3 + 4 = 7, 4 + 4 = 8 and so on so the equation is y = x + 4.

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What is the solution to the inequality?

oksano4ka [1.4K]

Alright, lets get started.

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Distributing $-\frac{2}{3}$ into parenthesis

$-\frac{4x}{3}+ \frac{2}{6} \leq \frac{x}{5} -1$

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Subtracting $\frac{1}{3}$ from both sides

$-\frac{4x}{3}+ \frac{1}{3}- \frac{1}{3}\leq\frac{x}{5}-1- \frac{1}{3}$

$-\frac{4x}{3} \leq \frac{x}{5}- \frac{4}{3}$

Adding $\frac{4}{3}$ in both sides

$-\frac{4x}{3}+ \frac{4}{3} \leq \frac{x}{5} -\frac{4}{3}+ \frac{4}{3}$

$-\frac{4x}{3} +\frac{4}{3} \leq \frac{x}{5}$

Adding $\frac{4x}{3}$ in both sides

$-\frac{4x}{3} +\frac{4}{3} +\frac{4x}{3} \leq \frac{x}{5} +\frac{4x}{3}$

$\frac{4}{3} \leq \frac{x}{5} +\frac{4x}{3}$

Making common denominator, adding fractions

$\frac{4}{3} \leq \frac{23x}{15}$

It means

$23x\geq \frac{4*15}{3}$

$23x\geq 20$

Dividing 23 in both sides

$x\geq \frac{20}{23}$

In interval notation

[ $\frac{20}{23}$ ,∞)

This is the answer

Hope it will help :)

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3 years ago

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Step-by-step explanation:

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