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vodka [1.7K]
3 years ago
14

What is the determinant of 1518154

Mathematics
1 answer:
IgorC [24]3 years ago
6 0

Answer:

The determinant is 15.

Step-by-step explanation:

You need to calculate the determinant of the given matrix.

1. Subtract column 3 multiplied by 3 from column 1 (C1=C1−(3)C3):

\left[\begin{array}{ccc}-25&-23&9\\0&3&1\\-5&5&3\end{array}\right]

2. Subtract column 3 multiplied by 3 from column 2 (C2=C2−(3)C3):

\left[\begin{array}{ccc}-25&-23&9\\0&0&1\\-5&-4&3\end{array}\right]

3. Expand along the row 2: (See attached picture).

We get that the answer is 15. The determinant is 15.

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Which of the following scatterplots would have a trend line with a positive slope?
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2 years ago
Find the derivative of sinx/1+cosx, using quotient rule​
Mrrafil [7]

Answer:

f'(x) = -1/(1 - Cos(x))

Step-by-step explanation:

The quotient rule for derivation is:

For f(x) = h(x)/k(x)

f'(x) = \frac{h'(x)*k(x) - k'(x)*h(x)}{k^2(x)}

In this case, the function is:

f(x) = Sin(x)/(1 + Cos(x))

Then we have:

h(x) = Sin(x)

h'(x) = Cos(x)

And for the denominator:

k(x) = 1 - Cos(x)

k'(x) = -( -Sin(x)) = Sin(x)

Replacing these in the rule, we get:

f'(x) = \frac{Cos(x)*(1 - Cos(x)) - Sin(x)*Sin(x)}{(1 - Cos(x))^2}

Now we can simplify that:

f'(x) = \frac{Cos(x)*(1 - Cos(x)) - Sin(x)*Sin(x)}{(1 - Cos(x))^2} = \frac{Cos(x) - Cos^2(x) - Sin^2(x)}{(1 - Cos(x))^2}

And we know that:

cos^2(x) + sin^2(x) = 1

then:

f'(x) = \frac{Cos(x)- 1}{(1 - Cos(x))^2} = - \frac{(1 - Cos(x))}{(1 - Cos(x))^2} = \frac{-1}{1 - Cos(x)}

4 0
3 years ago
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Jac fxddmcrrnfhthfjgjjfjffjfhfjthht tntnfntj4r

5 0
3 years ago
Read 2 more answers
Solve this problem please :)
zvonat [6]
The Answer is B 8/3 :)
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2 years ago
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