What is the determinant of 1518154

Mathematics

1 answer:

IgorC [24]3 years ago

6 0

Answer:

The determinant is 15.

Step-by-step explanation:

You need to calculate the determinant of the given matrix.

1. Subtract column 3 multiplied by 3 from column 1 (C1=C1−(3)C3):

$\left[\begin{array}{ccc}-25&-23&9\\0&3&1\\-5&5&3\end{array}\right]$

2. Subtract column 3 multiplied by 3 from column 2 (C2=C2−(3)C3):

$\left[\begin{array}{ccc}-25&-23&9\\0&0&1\\-5&-4&3\end{array}\right]$

3. Expand along the row 2: (See attached picture).

We get that the answer is 15. The determinant is 15.

You might be interested in

What is the surface area of this design ?

Fed [463]

Answer:

384 8x8=64 64x2=128 128x3=384

Step-by-step explanation:

8 0

3 years ago

Find the value of x and y

vova2212 [387]

let's first off take a look at the tickmarks, three side tickmarks, so all those 3 sides are equal, all have a length of y - 25, so is an equilateral triangle.

there are two angle tickmarks, meaning those two angles are equal, wait a second! if those two angles are equal, that means is an isosceles triangle.

now, in an equilateral triangle, all sides are equal, but also all angles are equal, since the sum of all interior angles is 180°, then each angle is really 60°.

let's notice that angle on the upper-left-corner, is a right-angle, but 60° are on the equilateral triangle, and so the remaining 30° must be on the isosceles triangle.

the isosceles triangle has then a vertex of 30°, and twin angles, the twin angles let's say are each a° so then

30° + a° + a° = 180°

30 + 2a = 180

2a = 150

a = 75° = y

now, let's recall, the isosceles triangle has twin angles but it also has twin sides, so the side "x" and the side with the tickmark are equal.

well, we know that y = 75, so the sides with the tickmark are then (75) - 25 = 50 = x.

5 0

3 years ago

Explain the distance formula. Then use it to calculate the

Alex777 [14]

Answer:

$dAB=10\ units$

Step-by-step explanation:

we know that

The distance formula is derived by creating a triangle and using the Pythagorean theorem to find the length of the hypotenuse. The hypotenuse of the triangle is the distance between the two points

The formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$