Answer:
<em>A special right triangle is a right triangle with some regular feature that makes calculations on the triangle easier, or for which simple formulas exist. For example, a right triangle may have angles that form simple relationships, such as 45°–45°–90°. This is called an "angle-based" right triangle.</em>
Step-by-step explanation:
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Answer:
<em>The correct answer is: A</em>
Step-by-step explanation:
<u>Points on a Numeric Line</u>
The numeric line shown in the figure has four points A, B, C, and D. It's clear that each marked division of the line has a value of 1/4 units and all four points are below the reference zero, thus all are negative.
Point A is clearly on the -2 mark, thus
A=-2
Point B is one mark above A, thus it's located at:


Point C is one mark below -1, thus:

Finally, point D is one mark below 0:

The correct answer is: A
Answer:
9.34%
Step-by-step explanation:
p = 4%, or 0.04
n = Sample size = 667
u = Expected value = n * p = 667 * 0.04 = 26.68
SD = Standard deviation =
= 5.06
Now, the question is if the manager is correct, what is the probability that the proportion of flops in a sample of 667 released films would be greater than 5%?
This statement implies that the p-vlaue of Z when X = 5% * 667 = 33.35
Since,
Z = (X - u) / SD
We have;
Z = (33.35 - 26.68) / 5.06
Z = 1.32
From the Z-table, the p-value of 1.32 is 0.9066
1 - 0.9066 = 0.0934, or 9.34%
Therefore, the probability that the proportion of flops in a sample of 667 released films would be greater than 5% is 9.34%.
Answer:
21
Step-by-step explanation:
5×3=15
7×3=21
Answer:
P = 0.008908
Step-by-step explanation:
The complete question is:
The table below describes the smoking habits of a group of asthma sufferers
Nonsmokers Light Smoker Heavy smoker Total
Men 303 35 37 375
Women 413 31 45 489
Total 716 66 82 864
If two different people are randomly selected from the 864 subjects, find the probability that they are both heavy smokers.
The number of ways in which we can select x subjects from a group of n subject is given by the combination and it is calculated as:

Now, there are 82C2 ways to select subjects that are both heavy smokers. Because we are going to select 2 subjects from a group of 82 heavy smokers. So, it is calculated as:

At the same way, there are 864C2 ways to select 2 different people from the 864 subjects. It is equal to:

Then, the probability P that two different people from the 864 subjects are both heavy smokers is:
