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inysia [295]
3 years ago
8

How to do the problem

Mathematics
1 answer:
marta [7]3 years ago
6 0
There are 153 people who each ate 1/4 pounds. Therefore, the amount of watermelon eaten is 153/4 pounds.
The amount of watermelon served is
8 \frac{1}{4}  + 9 \frac{1}{4}  + 8 \frac{7}{8}  + 9 \frac{5}{8}  + 10 \frac{3}{4}
=  \frac{8 \times 4 + 1}{4}  +  \frac{9 \times 4 + 1}{4}  \\  +  \frac{8 \times 8 + 7}{8}  +  \frac{9 \times 8 + 5}{8} \\  +  \frac{10 \times 4 + 3}{4}
=  \frac{33}{4}  +  \frac{37}{4}  +  \frac{71}{8}  +  \frac{77}{8}  +  \frac{43}{4}  \\  =  \frac{33 \times 2}{4 \times 2}  +  \frac{37 \times 2}{4 \times 2}  +  \frac{71}{8}  \\  +  \frac{77}{8}  +  \frac{43 \times 2}{4 \times 2}
=  \frac{66 + 74 + 71 + 77 + 86}{8}
=  \frac{374}{8}  =  \frac{186}{4}
There is 186/4 total watermelon. Minus the 153/4 that was eaten,
\frac{186 - 153}{4}  =  \frac{33}{4}  = 8 \frac{1}{4}

The leftover watermelon is 8 & 1/4 pounds.
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\text{D) If }EFG \cong HJK, \text{ then } HJK \cong EFG.

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No, Dale Isn't correct because 3:5 is greater than 2:10

Step-by-step explanation:

3:5 and 2:10 is the same as in \frac{3}{5}  and \frac{2}{10}

First Find the least common denominator or LCM of the two denominators:

LCM of 5 and 10 is 10

Next, find the equivalent fraction of both fractional numbers with denominator 10

For the 1st fraction, since 5 × 2 = 10,

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Likewise, for the 2nd fraction, since 10 × 1 = 10,

\frac{2}{10} =\frac{2*1}{10*1} =\frac{2}{10}

Since the denominators are now the same, the fraction with the bigger numerator is the greater fraction

\frac{6}{10} >\frac{2}{10} Or\frac{3}{5} >\frac{2}{10}

Hence, \frac{3}{5} is <u>Greater than </u>\frac{2}{10}

Hence, 3:5 is <u>Greater than </u>2:10

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