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Llana [10]
3 years ago
5

There are 8 performers who will present their comedy acts this weekend at a comedy club. One of the performers insists on being

the last stand up comic of the evening. If this performers request is granted, how many different ways are there to schedule there appearences?
Mathematics
1 answer:
Natalija [7]3 years ago
5 0
Well, the keyword here is One of the performers insist on being the last.

So, the amount of performers that we can arrange freely is 7 performers.

Different ways we can schedule their appearance is :

7 ! = 7 x 6  x 5 x 4 x 3 x 2 x 1
   
 
    = 5040

hope this helps
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