Answer:
he will overdraw his bank account by at least $25
Step-by-step explanation:
Answer:
Step-by-step explanation:
-3x^4 -9x^3+ 15x^2
-3x^2 ( x^2 + 3x -5)
if you use quadratic formula (see image)
~~~~~~~~~~~~~~~~~~~~~~
10x^3 -35x^2 +6x -21
5x2(2x-7) +3(2x-7)
(5
+ 3) (2x-7)
<h3 /><h3>
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Equation for Perimeter of a rectangle: Perimeter = 2W + 2L
<h3>Defining the variables, let</h3>
<h3>Width = x</h3><h3>Length = 2x+3 (3 more than twice the width)</h3>
<h3>Plugging everything into the equation</h3>
<h3>30= 2(x) + 2(2x+3) using the distributive property,</h3>
<h3>30=2x+4x+6 combining like terms</h3>
<h3>30=6x+6 subtracting 6 from both sides,</h3>
<h3>24=6x divide both sides by 6</h3>
<h3>4=x This means that the width is 4 m.</h3>
<h3>To get the length, use the expression L=2x+3 and plug in x = 4 that was already solved for</h3>
<h3>L=2(4)+3</h3>
<h3>L=8+3 = 11 m</h3>
<h3>So the dimensions of the rectangle are width is 4 m and length is 11 m.</h3>
-x + 4 = 2x + 1
add x to both sides
4 = 3x + 1
subtract 1 from both sides
3 = 3x
dived 3 from both sides
1 = x
This problem is a multi step problem. All you have to do is break it down into parts to make it easier. We can start by finding the diameter of the inner circle.
1. circumference = πd (Since the circumference is given as 44, and we know to use 22/7 for π, divide 44 by 22/7 to get d.)
44 / 22/7 = about 14.0 when rounded
2. Now add +8 to the 14 since we know that there are 4 ft. on both sides of the small inner circle.
14 + 8 = 22
3) The last step gave us the diameter of the bigger outer circle. Now, we have to plug in the 22 for d in the formula for circumference to find the circumference of the outer circle.
c = πd → c = 22 * 22/7 = 484/7 (484/7 = about 69 when rounded as a decimal)
4) The last step now is to subtract the circumferences, since the problem was asking for how much greater the outer circle's circumference is than the inner circle.
69 - 44 = 25
Your answer should be about 25 ft.
********** Note the answer they are looking for may be slightly different depending on whether they were looking for a fraction or decimal answer and where they rounded. ********************************************************
