How does the area of triangle RST compare to the area of triangle LMN? The area of △RST is 2 square units less than the area of
△LMN. The area of △RST is equal to the area of △LMN. The area of △RST is 2 square units greater than the area of △LMN. The area of △RST is 4 square units greater than the area of △LMN.
2 answers:
Inscribe triangle RST in the square with dimensions 4×4, as shown in the figure.
from the area of this square, 4*4=16, we remove the triangles with dimensions
3×4, 2×1 and 2×4, whose side lengths are shown in the figure, and we are left with the area of triangle RST.
so
units squared
similarly,
units squared
Thus, the areas are equal.
from the area of this square, 4*4=16, we remove the triangles with dimensions
3×4, 2×1 and 2×4, whose side lengths are shown in the figure, and we are left with the area of triangle RST.
so
similarly,
Thus, the areas are equal.
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Answer and Step-by-step explanation: The described right triangle is in the attachment.
As it is shown, AC is the hypotenuse and BC and AB are the sides, so use Pytagorean Theorem to find the unknown measure:
AC² = AB² + BC²
AB = 5.4
Then, right triangle ABC measures:
AB = 5.4cm
BC = 4.5cm
AC = 7cm
Answer:
sin a = 7/25
cos a = 24/25
tan a = 7/24
Step-by-step explanation:
Trig. How wonderful. I get tripped up on these types of problems some times, so I decided to try to help! To start, write out the three ratios.
SOH (sine=opposite/hypotenuse) CAH (cosine=adjacent/hypotenuse) TOA (tangent=opposite/adjacent)
Then, label the triangle with “hypotenuse” “adjacent” and “opposite.” This helps us correctly use and find the raitos. Then, use these ratios to find out the ratios of A!
sin a = 7/25
cos a = 24/25
tan a = 7/24
If needed, just divide the ratios to get their decimal form!
