Find the slope of the line below.

Given: O is the midpoint of line MN OM=OW Prove: OW=ON

grigory [225]

Given:
O is the midpoint of line MN
OM = OW

To prove: OW = ON

Statement Reason
1> OM = OW -------------------------> Given
2> OM = ON ---------------------------> O is the midpoint of line MN
 i.e Point O bisects line MN
3> OM = OW --------------------------> From statement <1>
4> ON = OW -------------------------> OM = ON (Statement <2>)
OW = ON

 proved!!

6 0

3 years ago

Choose the linear inequality that describes the graph. The gray area represents the shaded region

Vesnalui [34]

(0,3)(1,-2)
slope = (-2-3) / (1 - 0) = -5

y int is (0,3)

line is dashed, means no equal sign....shading above the line, means greater then

ur inequality is : y > -5x + 3

6 0

3 years ago

Read 2 more answers

In a list of households, own homes and do not own homes. Five households are randomly selected from these households. Find the p

hichkok12 [17]

Answer:

The probability of success for this case would be:

$p =\frac{9}{15}= 0.6$ representing the proportion of homes that are own homes

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=15, p=0.6)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

And we want this probability:

$P(X=3)$

And uing the probability mass function we got:

$P(X=3)= 15C3 (0.6)^3 (1-0.6)^{15-3}= 0.00165$

Step-by-step explanation:

Adduming the following info: In a list of 15 households, 9 own homes and 6 do not own homes. Five households are randomly selected from these 15 households. Find the probability that the number of households in these 5 own homes is exactly 3.

Round your answer to four decimal places

P (exactly 3)=

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

The probability of success for this case would be:

$p =\frac{9}{15}= 0.6$ representing the proportion of homes that are own homes

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=15, p=0.6)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^{n-x}$

Where (nCx) means combinatory and it's given by this formula:

$nCx=\frac{n!}{(n-x)! x!}$

And we want this probability:

$P(X=3)$

And uing the probability mass function we got:

$P(X=3)= 15C3 (0.6)^3 (1-0.6)^{15-3}= 0.00165$

4 0

3 years ago

Enter the equation of the circle described below. Center (-3, 0), radius sqrt 5

stealth61 [152]

Hello :
 the equation of the circle is (x-a)²+(y-b)² = r²
A(a;b) center r : radius
in this exercice : (x+3)²+y²=25

3 0

3 years ago

Read 2 more answers

Please find the area

DENIUS [597]

Answer: 55

Explanation:
Find the area of the entire shape: 7x9=63
Find the area of the missing piece: 8
7-3=4 9-5=4 4x4=16 16/2=8
Find the area: 63-8=55

3 0

3 years ago