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2 years ago

Decompose the mixed number 1 3/5

Mathematics

1 answer:

Alex787 [66]2 years ago

7 0

Answer: 8/5

Step-by-step explanation: 1x5+3=8/5

please mark as brainliest! :)

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Can y’all help me answer these questions

cupoosta [38]

2. $f(x)=\dfrac18\left(\dfrac14\right)^{x-2}$

Domain: $(-\infty,\infty)$ , because any value of $x$ is allowed and gives a number $f(x)$ .

Range: $(0,\infty)$ , because $a^x>0$ for any positive real $a\neq0$ .

y-intercept: This is a point of the form $(0, f(0))$ . So plug in $x=0$ ; we get $f(0)=\frac18\left(\frac14\right)^{-2}=\frac{4^2}8=2$ . So the intercept is (0, 2), or just 2. (Interestingly, you didn't get marked wrong for that...)

Asymptote: This can be deduced from the range; the asymptote is the line $y=0$ .

Increasing interval: Going from left to right, there is no interval on which $f(x)$ is increasing, since 1/4 is between 0 and 1.

Decreasing interval: Same as the domain; $f(x)$ is decreasing over the entire real line.

End behavior: The range tells you $f(x)>0$ , and you know $f(x)$ is decreasing over its entire domain. This means that $f(x)\to+\infty$ as $x\to-\infty$ , and $f(x)\to0$ and $x\to+\infty$ .

3. $f(x)=\left(\dfrac32\right)^{-x}-7$

Domain: Same as (2), $(-\infty, \infty)$ .

Range: We can rewrite $f(x)=\left(\frac23\right)^x-7$ . $\left(\frac23\right)^x>0$ for all $x$ , so $\left(\frac23\right)^x-7>-7$ for all $x$ . Then the range is $(-7,\infty)$ .

y-intercept: We have $f(0)=\left(\frac32\right)^0-7=1-7=-6$ , so the intercept is (0, -6) (or just -6).

Asymptote: $y=-7$

Increasing interval: Not increasing anywhere

Decreasing interval: $(-\infty,\infty)$

End behavior: Similar to (2), but this time $f(x)\to+\infty$ as $x\to-\infty$ and $f(x)\to-7$ as $x\to+\infty$ .

5 0

3 years ago

Write a comparison statement for the depth of the hermit crab and the redfish.

Delicious77 [7]

2 ft > -3 ft
The redfish is deeper than the hermit crab.

8 0

3 years ago

Solve 2x^3+7x^2-2x-1=o

Mashcka [7]

Answer:

$x=\sqrt{3}-2\\x=-\sqrt{3}-2\\x=\frac{1}{2}$

Step-by-step explanation:

This is a hard one

We have to use the rational root theorem

$2x^3+7x^2-2x-1$ = 0

We have to find all the factors of a and d and put them in a fraction

$a=2\\d=-1\\\frac{1}{1,2}$

We then plug them into the equation to see if any of them work

The equation isn't true when plugging 1, but is true when plugging in 1/2

factored form of 1/2 is (2x-1)

Then we divide the original equation by (2x-1) (you can use synthetic division or long division, it would be hard to type out the process for that) to get $x^2+4x+1$