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4 years ago

As the atoms in period 3 of the periodic table are considered from left to right, the atoms generally show

Mathematics

1 answer:

Gala2k [10]4 years ago

8 0

In row 3 of the periodic table, the third electron shell (the "M" Shell) is being filled in.

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Please match each function formula with the corresponding transformation of the parent function y= -x^2-1

pishuonlain [190]

Answer:

The answer in the attached figure

Step-by-step explanation:

we have the parent function

$y=-x^{2}-1$

case 1) <u>Reflected across the x-axis</u>

we know that

The rule of the transformation is

(x,y)------> (x,-y)

$y=-(-x^{2}-1)$

$y=x^{2}+1$

case 2) <u>Reflected across the y-axis</u>

we know that

The rule of the transformation is

(x,y)------> (-x,y)

$y=-(-x)^{2}-1$

$y=-x^{2}-1$

case 3) Translated left by 1 unit

we know that

The rule of the transformation is

(x,y)------> (x-1,y)

$y=-(x+1)^{2}-1$

case 4) Translated right by 1 unit

we know that

The rule of the transformation is

(x,y)------> (x+1,y)

$y=-(x-1)^{2}-1$

case 5) Translated down by 1 unit

we know that

The rule of the transformation is

(x,y)------> (x,y-1)

$y=-(x)^{2}-1-1$

$y=-(x)^{2}-2$

case 6) Translated up by 1 unit

we know that

The rule of the transformation is

(x,y)------> (x,y+1)

$y=-(x)^{2}-1+1$

$y=-(x)^{2}$

8 0

3 years ago

Kelly has 24 dimes and quarters worth $3.60. How many quarters does she have?

son4ous [18]

Should be around 5 (five) quarters

7 0

3 years ago

Read 2 more answers

TRIGONOMETRY - Given the complex numbers <img src="https://tex.z-dn.net/?f=z_%7B1%7D%20%3D20%20cis%20226" id="TexFormula1" title

Norma-Jean [14]

This is easily done after writing both complex numbers in exponential form:

$z_1=20\,\mathrm{cis}226^\circ=20e^{226^\circ i}$

$z_2=5\,\mathrm{cis}76^\circ=5e^{76^\circ i}$

Then

$\dfrac{z_1}{z_2}=\dfrac{20e^{226^\circ i}}{5e^{76^\circ i}}=4e^{(226-76)^\circ i}=4e^{150^\circ i}$

In trigonometric form, this is

$\dfrac{z_1}{z_2}=4\,\mathrm{cis}150^\circ=4(\cos150^\circ+i\sin150^\circ)=\boxed{-\dfrac{\sqrt3}2+\dfrac i2}$

8 0

3 years ago

A car used 16 gallons of gasoline and traveled a total distance of 460 miles. The car's fuel efficiency is 30 miles per gallon o

AURORKA [14]

Answer:

12 gallons

Step-by-step explanation:

Total gallons = 16 gallons

Total distance = 460 miles

Fuel efficiency in the highway = 30 miles per gallon

Fuel efficiency in the city = 25 miles per gallon

Let

h = gallons of gasoline were used on the highway.

460 = 30h + 25(16 - h)

460 = 30h + 400 - 25h

460 - 400 = 30h - 25h

60 = 5h

h = 60/5

h = 12 gallons

12 gallons of gasoline were used on the highway.

7 0

3 years ago

(5.2c-7.35)+(-3.9c+2.65)

Effectus [21]

Answer:

1.3c - 4.69

Step-by-step explanation:

5.2 - 3.9 = 1.3

2.65 - 7.35 = -4.69

4 0

3 years ago