All categories

3 years ago

The ratio of the mass of an ant to the mass it can carry 1:50

Mathematics

1 answer:

slavikrds [6]3 years ago

6 0

The ratio 1:50 means that an ant can carry an object heavy 50 times its mass.

So, if the mass of the ant is 0.4 grams, it can carry at most 50 times that mass, i.e. 50x0.4 = 20 grams

In order to answer the second question, you need to consider your mass and multiply it by 50: if you were as strong as an ant, you could lift that weight!

You might be interested in

There are 4 roads leading from Bluffton to Hardeeville, 6 roads leading from Hardeeville to Savannah, and 5 roads leading from

Dmitrij [34]

Answer:

120 ways.

Step-by-step explanation:

From the given information:

Total number of roads leading from Bluffton to Hardeeville = 4

Total number of roads leading from Hardeeville to Savannah = 6

Total number of roads leading from Savannah to Macon = 5

We need to find the total number of ways to get from Bluffton to Macon.

Total number of ways to get from Bluffton to Macon = $4\times 6\times 5= 120$

Therefore, there are 120 required number of ways to get from Bluffton to Macon.

7 0

3 years ago

Find each percent of change. Round to the nearest whole percent if necessary. State whether the percent of change is an increase

Goryan [66]

Answer:

decrease

Step-by-step explanation:

5 0

3 years ago

Read 2 more answers

1. In the number 7563291 write down the column that the 5 is in

Tasya [4]

Answer:

Hundred Thousands
-4
90
a-b
6/14 = 3/7
1204
3500 & 3600
I am guessing but I am not sure on how to do this one. x=11
3/8(6)-1/6(8)=18/48-8/48=10/48=****5/24****
6.6 repeating
180-72=108-49=****59****
5,6,7,8,9
No number 13
60%
3.5 or if adding 7% tax then it is 53.50
8 edges

8 0

3 years ago

Enter <, >, or = to make the

AVprozaik [17]

Answer:

Step-by-step explanation:

3 0

2 years ago

Write the terms a 1a1, a 2a2, a 3a3, and a 4a4 of the following sequence. If the sequence appears to converge, make a conjec

Arturiano [62]

Answer:

Step-by-step explanation:

WE are given that $a_n = \frac{(-1)^{n+1}}{5n-4}$ . Then, to now the first for terms, we must replace n by 1,2,3,4 respectively. Then

$a_1 = \frac{(-1)^2}{5(1)-4} = \frac{1}{1}= 1$

$a_2 = \frac{(-1)^3}{5(2)-4} = \frac{-1}{6}$

$a_3 = \frac{(-1)^4}{5(3)-4} = \frac{1}{11}= 1$

$a_4 = \frac{(-1)^5}{5(4)-4} = \frac{-1}{16}= 1$

Note that as n increase, $a_n$ gets closer to 0. So, the limit of this sequence is 0.

6 0

3 years ago