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3 years ago

The ratio of the mass of an ant to the mass it can carry 1:50

Mathematics

1 answer:

slavikrds [6]3 years ago

6 0

The ratio 1:50 means that an ant can carry an object heavy 50 times its mass.

So, if the mass of the ant is 0.4 grams, it can carry at most 50 times that mass, i.e. 50x0.4 = 20 grams

In order to answer the second question, you need to consider your mass and multiply it by 50: if you were as strong as an ant, you could lift that weight!

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Russ is solving an equation where both sides are linear expressions. he sets the expressions equal to y and graphs the system fi

Dafna1 [17]

The correct option (D).

There are infinitely many intersection points.

<h3>What is liner equation?</h3>

a two-variable equation that, when plotted on a graph, results in a straight line.

<h3>What does intersection point mean?</h3>

The term "point of intersection" refers to the intersection of two lines.

<h3>According to the given information:</h3>

Russ is attempting to solve an equation whose two sides are both linear expressions.

He graphs the system and finds that they are on the same line after setting the expressions to y.

Since both lines are the same, there are an endless number of junction places.

Russ should therefore consider the outcome to be option (D) There are a limitless number of intersections.

To know more about intersection points and linear equations visit:

brainly.com/question/16982453

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I understand that the question you are looking for is:

Russ is solving an equation where both sides are linear expressions. He sets the expressions equal to y and graphs the system finding that they are the same line. How should Russ interpret this outcome? There are no intersection points. There is exactly one intersection point. There are exactly two intersection points. There are infinitely many intersection points.Russ is solving an equation where both sides are linear expressions. He sets the expressions equal to y and graphs the system finding that they are the same line. How should Russ interpret this outcome?

A. There are no intersection points.

B. There is exactly one intersection point.

C. There are exactly two intersection points.

D. There are infinitely many intersection points

3 0

1 year ago

Graph each function.<br> Which option is correct?

Gre4nikov [31]

Answer:

Answer is the second one

Step-by-step explanation:

Log

$log(x - 2)$

X-2 means it is shifted to the right by 2 units also there is no negative before log so it os not reflected

7 0

3 years ago

If you roll two four-sided dice numbered 1, 2, 3, and 4), what is the probability that the sum of the dice is 7? Enter a fractio

Anna [14]

The probability that the sum of the dice is 7 is 1/2 because there are only three combinations that result in the sum of 7: (1,6)(2,5) and (3,4). But there are 6 possible outcomes( this is if you don’t add reverse combinations such as 1,6 and 6,1) so the probability would be 3/6 or 1/2

8 0

3 years ago

Solve by elimination

DiKsa [7]

2x-y=-8
+
y=2
2x=-6
x=-3
2*-3-y=-8
-6-y=-8
-y=-2

x=-3 and y=2

7 0

2 years ago

What is the probability of rolling a four then a three

spayn [35]

Answer:

$\frac{1}{36}$

Step-by-step explanation:

Total possibilities when we a roll a die at a time are 6

given we should have four for first time and then three

let us assume we rolled the dice we may get 1,2,3,4,5,6(any of these) the probability to get 4 is

PROBABILITY= $\frac{\textrm{FAVOURABLE CHANCES}}{\textrm{TOTAL CHANCES}}$

Favourable chances=1

Total chances=6

Probability= $\frac{1}{6}$

the prabability to get 4 in first roll is $\frac{1}{6}$ .

let us assume we rolled the dice for second time again we may get 1,2,3,4,5,6(any of these) the probability to get 3 is

Favourable chances=1

total chances=6

probability= $\frac{1}{6}$

the probability to get 3 in second roll irrespective of first one is $\frac{1}{6}$

the probability to get 4 in first time and then 3 is

The probability to occur both events at a time is multiplication of individual probabilities

So,

probablility to get 4 in first roll= $\frac{1}{6}$

probability to get 3 in second roll= $\frac{1}{6}$

probability to occur both at a same time is = $\frac{1}{6}$ $\times$ $\frac{1}{6}$ = $\frac{1}{36}$

6 0

2 years ago