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2 years ago

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Mathematics

1 answer:

Slav-nsk [51]2 years ago

7 0

38 ma)a mamma mamahbahwnnwhshsjhsjsjwjsjsjshsuhs

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Please help me it’s due right now?!?! <br> Find the missing side of each triangle.

Sever21 [200]

Answer:

x = 2√5

Step-by-step explanation:

Using the Pythagorean Theorem:

a² + b² = c²

You can identify that x is the hypotenuse, as it is opposite to the right angle.

So:

3² + √11² = x²

9 + [(√11) (√11)] = x²

9 + 11 = x²

20 = x²

√20 = √x²

√4√5 = x

2√5 = x

x = 2√5

7 0

2 years ago

1. VIDEOTAPES Lyle is putting his

andrezito [222]

Answer:

12 divided by 1.5 = 8 tapes

Hope this helps you

5 0

2 years ago

Read 2 more answers

Type the correct answer in each box.

Mariulka [41]

Answer:

$(x-5)^2+(y+4)^2=100$

Step-by-step explanation:

step 1

Find the radius of the circle

we know that

The distance between the center and any point that lie on the circle is equal to the radius

we have the points

(5,-4) and (-3,2)

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

substitute the values

$r=\sqrt{(2+4)^{2}+(-3-5)^{2}}$

$r=\sqrt{(6)^{2}+(-8)^{2}}$

$r=\sqrt{100}\ units$

$r=10\ units$

step 2

Find the equation of the circle

we know that

The equation of a circle in standard form is equal to

$(x-h)^2+(y-k)^2=r^2$

where

(h,k) is the center

r is the radius

we have

$(h,k)=(5,-4)\\r=10\ units$

substitute

$(x-5)^2+(y+4)^2=10^2$

$(x-5)^2+(y+4)^2=100$

6 0

2 years ago

During a visit to the tide pools, Brent observed 16 sea stars, 4 sea urchins, and 52 sea anemones. What is the ratio of sea anem

weeeeeb [17]

Answer:

16 to 52

Step-by-step explanation:

7 0

2 years ago

A researcher is interested in determining if the more than two thirds of students would support making the Tuesday before Thanks

Yakvenalex [24]

Answer:

The null hypothesis is, {H₀}: p = 0.66, H₀: p = 0.66 .

The alternative hypothesis is, {Hₐ}: p > 0.66, Hₐ: p > 0.66

Step-by-step explanation:

Let p represent the proportion of students who are supportive of making the day before Thanksgiving a holiday.

Since two populations are considered, the alternative hypothesis for the difference of the means of the two populations has to be stated.

The proportion of two-third students are supportive of making the day before Thanksgiving a holiday is p = 0.66 obtained as shown below:

The null hypothesis is,

{H₀}:p = 0.66, H₀: p = 0.66

The alternative hypothesis is,

{Hₐ:p > 0.66, Ha: p > 0.66

The null hypothesis is, {H₀}: p = 0.66, H₀: p=0.66 .

The alternative hypothesis is, {Hₐ}: p > 0.66, Hₐ: p > 0.66

3 0

2 years ago