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4 years ago

8 yd. 1 ft. 1 in. + 6 yd. 2 ft. 8 in.

1 answer:

6 0

549 in. if you add everything up.
45.75 ft.
15.25 yd.
36 in. in 1 yd.
12 in. in 1 ft.

I think this is what you meant... hope this helps and if it isn't what you need just tell me. =)

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What is the answer to -6x - 11 = 19 And how to solve it?

liubo4ka [24]

-6x-11=19/+11 <=>

<=> -6x=30/:(-6) <=>

<=> x=-5

3 0

1 year ago

Q(a+y)=67y+93 Solve for y

bekas [8.4K]

Qa + Qy = 67y + 93
Qy - 67y = 93 - Qa
y(Q - 67) = 93 - Qa
y = $\frac{93-Qa}{Q-67}$

6 0

3 years ago

Read 2 more answers

Help me pleaseeeeeeeee

Hitman42 [59]

Answer:

Subtract 5 from each side

Step-by-step explanation:

This would put all coefficients on one side.

7 0

3 years ago

someone please explain to me how to find the area PLEASE! Find the area and perimeter of quadrilateral ABCD below. Explain your

Lunna [17]

Answer:

Part A) The area of the figure is $24\ units^{2}$

Part B) The perimeter of the figure is $20\ units$

Step-by-step explanation:

step 1

Find the area of the figure

we know that

The area of the figure is equal to the area of triangle ABD plus the area of triangle BCD

The area of triangle is equal to

$A=\frac{1}{2}bh$

Area of triangle ABD

Observing the graph

$b=BD=(-2+8)=6\ units$

$h=(9-5)=4\ units$

substitute

$A=\frac{1}{2}(6)(4)=12\ units^{2}$

Area of triangle BCD

Observing the graph

$b=BD=(-2+8)=6\ units$

$h=(5-1)=4\ units$

substitute

$A=\frac{1}{2}(6)(4)=12\ units^{2}$

The area of the figure is

$12\ units^{2}+12\ units^{2}=24\ units^{2}$

step 2

Find the perimeter of the figure

we know that

The perimeter of the figure is equal to

$P=AB+BC+CD+AD$

we have

$A(-5,1),B(-8,5),C(-5,9),D(-2,5)$

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

Find the distance AB

$d=\sqrt{(5-1)^{2}+(-8+5)^{2}}=5\ units$

Find the distance BC

$d=\sqrt{(9-5)^{2}+(-5+8)^{2}}=5\ units$

Find the distance CD

$d=\sqrt{(5-9)^{2}+(-2+5)^{2}}=5\ units$

Find the distance AD

$d=\sqrt{(5-1)^{2}+(-2+5)^{2}}=5\ units$

substitute the values

$P=5+5+5+5=20\ units$

7 0

3 years ago

Step by step plz 2x^2 + x - 3

Aleks04 [339]

Answer:

x = 1 or x = -3/2

Step-by-step explanation:

Solve for x over the real numbers:

2 x^2 + x - 3 = 0

The left hand side factors into a product with two terms:

(x - 1) (2 x + 3) = 0

Split into two equations:

x - 1 = 0 or 2 x + 3 = 0

Add 1 to both sides:

x = 1 or 2 x + 3 = 0

Subtract 3 from both sides:

x = 1 or 2 x = -3

Divide both sides by 2:

Answer: x = 1 or x = -3/2

7 0

3 years ago