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BigorU [14]
3 years ago
15

Greg is working on a school project

Mathematics
2 answers:
lyudmila [28]3 years ago
5 0

Answer: Cool

Step-by-step explanation:

Greg is working on a school project

Delicious77 [7]3 years ago
4 0

Answer:

noice

Step-by-step explanation:

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Answer:

98 and 105

Step-by-step explanation:

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3 years ago
Pls only do this if yk it because i’m giving correct answer brainliest! :))
Leno4ka [110]

Answer:

x=2+\frac{1}{2}\sqrt[]{21}

or

x=2-\frac{1}{2}\sqrt{{21}

Step-by-step explanation:

4x^2-16x-26=-21

Add 21 on both sides.

4x^2-16x-26+21=-21+21

4x^2-16x-5=0

a=4

b=-16

c=-5

x=\frac{-b\frac{+}{}\sqrt[]{b^2-4ac}  }{2a}

x=\frac{-(-16)\frac{+}{}\sqrt[]{(-16)^2-4(4)(-5)}  }{2(4)}

x=\frac{16\frac{+}{}\sqrt[]{256+80}  }{8}

x=\frac{16\frac{+}{}\sqrt[]{336}  }{8}

x=\frac{16\frac{+}{}\sqrt[]{2^2*2^2*21}  }{8}

x=\frac{16\frac{+}{}2*2\sqrt[]{21}  }{8}

x=\frac{16\frac{+}{}4\sqrt[]{21}  }{8}

---------------------------------------------------------------------------

x=\frac{16}{8}+\frac{4\sqrt[]{21}}{8}

x=2+\frac{1}{2}\sqrt[]{21}

---------------------------------------------------------------------------

x=\frac{16}{8}-\frac{4\sqrt[]{21}}{8}\\x=2-\frac{1}{2}\sqrt{{21}

6 0
2 years ago
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3 years ago
How do I divide fractions when one of them is a while number?​
ElenaW [278]

Answer:

change it to a mix fraction instead

Step-by-step explanation:

7 0
3 years ago
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