So an example
least common multipule is like what is
the smallest number both will fit into
example, 6 and 10, least common
multilule is 30 because 6*5=30 and 3*10=30
so 3 and 4
factor each
3=3
4=2*2
so we have to have 2*2*3 which is 12
12 is least common multiplule
Answer:
52.4 cm
Step-by-step explanation:
Circumference of a circle = 2πr
Radius, r = diameter / 2
= 17 cm / 2
= 8.5 cm
π = 3.14
Circumference of a circle = 2πr
= 2 × 3.14 × 8.5
= 53.38 cm
Approximately 52.4 cm
If x is the first of the integers then the statement is:
(x) , (x+2) , (x+4) , (x+6)
This means that the smallest is x and the largest is x + 6
so:
3(x) + 2(x+6) = 293
3x + 2x + 12 = 293
5x = 281
x = 56.2
This gives us a none integer (decimal)
What now?
Wait remember how x started as the lowest? what if x was the highest instead?
x, x-2, x-4, x-6
so:
3(x-6) + 2(x) = 293
5x = 315
x = 62.2
This is as close as have gotten to the answer
Cant seem to get an integer.
Maybe error in the question or some bad math on my part.
Parentheses. Exponents. Multiplication Division. Addition Subtraction.
2) 6 x (11 - 5)- 7^2
6 x (6) - 7^2
6 x 6 - 49
36 - 49
-13
3) (40 - 2^2) / (-4 + 6)
(40 - 4) / (-4 + 6)
(36) / (2)
36/2
13/1
13
4) (66 - 6) / 6 - 2^2
(60) / 6 - 2^2
60 / 6 - 4
60 / 2
30 / 1
30
