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3 years ago

Please anyone help me

Mathematics

1 answer:

docker41 [41]3 years ago

8 0

<h2>Math Problem </h2>

If die is rolled two times, find the probably of getting "1'twice.

<h2>Math Answer </h2>

${1}\{36}$

Feel fre e too ask me 

Please understand it

#BrainliestBunch

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A farmer has 107 acres on which to plant oats or corn. Each acre of oats requires $18 capital and 2 hours of labor. Each acre of

Lera25 [3.4K]

Answer:

Step-by-step explanation:

the objective is to maximize profit

let x be corn and y be oat

let us begging by formulating the linear program for the problem

The objective function is

111x+47y=P

The constraints are

1. capital

36x+18y=2100------------1

2. labor

6x(8)+2y(8)=2400

48x+16y=2400-------------2

solving 1 and 2 we apply substitution method

36x+18y=2100------1

36x=2100-18y

x=(2100-18y)/36

put x=(2100-18y)/36 in 2 we have

48(2100-18y)/36+16y=2400

(100800-864y)/36+16y=2400

2800-24y+16y=2400

-8y=2400-2800

-8y=-400

8y=400

y=400/8

y=50

to find x put y=50 in 36x+18y=2100------------1

36x+18(50)=2100------------1

36x+900=2100

36x=2100-900

36x=1200

x=1200/36

x=33.33

profit is

111x+47y=P

111(33.33)+47(50)=P

3699.63+2350=P

P=6049.63

$6049.63

the planning comnination is to work on

33.33 acre of corn and 50 acre of oat

8 0

3 years ago

How do you solve 11x=24+8x

fgiga [73]

First bring all the x's to one side.
then subtract them.
then divide 24 by 3 to get the x alone and get your answer.

11x-8x=24
3x=24
x=8

3 0

4 years ago

Ninety six passengers rode a train. Tickets for regular coach seats are $114. Tickets for sleeper car seats are $295. The receip

MrRa [10]

C = amount of folks buying coach tickets
s = amount fo folks buying sleeper car tickets

we know the train had a total of 96 passengers, so, whatever "c" and "s" are
c + s = 96

we know all tickets sold for all 96 passengers was 19994, so, if "c" folks rode coach, each ticket is 114, thus 114*c is how much money was from couch, or 114c

if "s" folks rode the sleeper car, we know each ticket is 295 each, so 295*s is how much money was from the sleeper car

we also know, the total for all tickets is 19994

thus 114c + 295s = 19994

thus $\bf \begin{cases}
c+s=96\implies \boxed{s}=96-c\\
114c+295s = 19994\\
----------\\
114c+295\left( \boxed{96-c} \right)=19994
\end{cases}$

solve for "s", to see how many folks rode coach

what about the sleeper car? well, s = 96 - c

5 0

3 years ago

The area of a rectangle is 256.5m. If the length is 18m what is the perimeter of the rectangle?

irga5000 [103]

The area of a rectangle equals length times height. (A=LH)

A=256.5 L=18

Plugging in the numbers into the equation, you get 256.5=18H. (like I substituted the numbers in)

next if you divided both sides by 18, it will cancel out the 18 in the 18H side of the equation.

So, it is 256.5/18 equaling H

256.5 divided by 18 is... 14.25

That means the height is 14.25 an the length is 18.

the perimeter is all of the sides added together. in a rectangle, the sides opposite each other are the same.

So you have two sides that are 14.25 and two that are 18 meters long.

14.25+14.25+18+18 equals the perimeter then.

So the answer would be... 64.5!

5 0

3 years ago

Read 2 more answers

I really need help can someone do all of them (On the back of the sheet numbers 1 and 2 cross multiplaction please THANK YOU

SVEN [57.7K]

1) 2/3 <7/8
2) 2/4>2/6
3) 12000
4)
5)2x8=16
6) 9x4=36
4)1/3<3/4
5)3/4>1/4
6) Green group ate more pizza
7) Ben’s ride was longer
8)

The first 4 and 8 I didn’t do because I didn’t understand what they were asking for

4 0

4 years ago