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3 years ago

Suppose we want to choose 7 colors, without replacement, from 11 distinct colors.

Mathematics

1 answer:

Elan Coil [88]3 years ago

5 0

Answer:

(A) 1,663,200

(B)330

Step-by-step explanation:

(A) To do this you would just have to know the combimations formula which is $\frac{n!}{(n-r)!}$ and when you plug in the numbers you get $\frac{11!}{4!}$ which when simplified is $\frac{39,916,800}{24}$ which is 1,663,200

(B) To do this you would just have to know the permutation formula which is $\frac{n!}{r!(n-r)!}$ so if we plug in all of the numbers we would get $\frac{11!}{7!(4!)}$ then we can divide 7 from both sides so we get $\frac{(11)(10)(9)(8)}{(4)(3)(2)(1)}$ and when you simplify you get $\frac{7920}{24}$ which when reduced is 330

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Sladkaya [172]

Answer:

A right 4 down 5

Step-by-step explanation:

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3 years ago

What is the perimeter of a regular pentagon with a

choli [55]

Answer:the perimeter of the regular pentagon is 5x + 20

Step-by-step explanation:

The perimeter of a plane figure is the distance around the plane figure. The pentagon is a plane figure. It has 5 sides. Since it is a regular Pentagon, it means that all the sides are equal.

From the information given, the length of each side of the regular Pentagon is x + 4

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3 years ago

10n^{2} - 12 = -8 Please help

torisob [31]

The value for n is $\frac{\sqrt{10} }{5}$

<h3>solving for n</h3>

given data

10n^{2} - 12 = -8

making n the subject of the formula

10n^{2} = -8 + 12

10n^{2} = 4

divide through by 10

n^{2} = 4 / 10

finding the square root of both sides

n = square root ( 4 / 10 )

$n = \sqrt{\frac{4}{10}$

n = 0.632 or $\frac{\sqrt{10} }{5}$

Read more the subject of formula here: brainly.com/question/21140562

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2 years ago

A table showing Number, Value, and Total Value. The first row shows Pennies, with the entries, p, 0.01, and 0.01 p. The second r

Romashka [77]

Answer:

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Step-by-step explanation:

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3 years ago

Read 2 more answers

An eastbound train left at 12pm. Four hours later, a westbound train left the same station. At 8pm, the two trains were 400 mile

Ainat [17]

Answer:

Step-by-step explanation:

Gotta love these motion problems!

d = rt is what we need here to solve this, along with some logic.

If the EB (eastbound) train left at noon then at the end of its travels, at 8pm to be specific, it was traveling for 8 hours. Therefore, for the EB train, t = 8.

If the WB train left at 4 pm then at the end of its travels, also at 8pm, it was traveling for 4 hours. Therefore, for the WB train, t = 4.

The distance between the trains is given as 400 miles. That 400 mile distance is due to the fact that each train traveled a distance of rate*time. The distance the WB train traveled + the distance the EB train traveled = 400 miles. Now we just need to find out the distance each traveled in its respective time frame.

For the EB train. We already know that t = 8. We do not know how fast it's going, so rate is just r. In the distance formula, d = rt:

$d_{EB}=8r$

For the WB train. We already know that t = 4. We do not know this rate either, but we do know that it is traveling 10 mph faster than the EB train, so rate is r + 10. In the distance formula, d = rt:

$d_{WB}=4(r+10)$ and