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GarryVolchara [31]
3 years ago
9

Suppose we want to choose 7 colors, without replacement, from 11 distinct colors.

Mathematics
1 answer:
Elan Coil [88]3 years ago
5 0

Answer:

(A) 1,663,200

(B)330

Step-by-step explanation:

<u><em>(A) </em></u>To do this you would just have to know the combimations formula which is \frac{n!}{(n-r)!} and when you plug in the numbers you get \frac{11!}{4!} which when simplified is \frac{39,916,800}{24} which is 1,663,200

<u><em>(B)</em></u> To do this you would just have to know the permutation formula which is \frac{n!}{r!(n-r)!} so if we plug in all of the numbers we would get \frac{11!}{7!(4!)} then we can divide 7 from both sides so we get \frac{(11)(10)(9)(8)}{(4)(3)(2)(1)} and when you simplify you get \frac{7920}{24} which when reduced is 330

<u><em></em></u>

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