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vitfil [10]
3 years ago
13

What is the perimeter of a regular pentagon with a

Mathematics
1 answer:
choli [55]3 years ago
3 0

Answer:the perimeter of the regular pentagon is 5x + 20

Step-by-step explanation:

The perimeter of a plane figure is the distance around the plane figure. The pentagon is a plane figure. It has 5 sides. Since it is a regular Pentagon, it means that all the sides are equal.

From the information given, the length of each side of the regular Pentagon is x + 4

The perimeter of the regular Pentagon would be 5 times the length of each side. It becomes

5(x + 4) = 5x + 20

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Gala2k [10]

Answer:

The System of inequality is ,

1. y > 2 x + p

2. y < 2 x + p

Suppose we assign some values to p and q and draw its graph

And, then the inequality sign on both inequalities is reversed

3. y < 2 x + p

4. y > 2 x + p

And , then draw it's graph

it has been found that, the solution set of both the inequality remains same.That is there is no point or set of points , which satisfy both the system of inequality.

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Analyze the diagram below and complete the instructions that follow.
valentinak56 [21]

Answer:

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General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtract Property of Equality

<u>Algebra I</u>

  • Terms/Coefficients/Degrees
  • Expand by FOIL (First Outside Inside Last)
  • Factoring
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<u>Trigonometry</u>

[Right Triangles Only] Pythagorean Theorem: a² + b² = c²

  • a is a leg
  • b is another leg
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Step-by-step explanation:

<u>Step 1: Identify</u>

<em>a</em> = x + 3

<em>b</em> = x

<em>c</em> = √117

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Substitute [PT]:                                                                                                (x + 3)² + x² = (√117)²
  2. Expand [FOIL]:                                                                                                 x² + 6x + 9 + x² = (√117)²
  3. Combine like terms:                                                                                       2x² + 6x + 9 = (√117)²
  4. Exponents:                                                                                                      2x² + 6x + 9 = 117
  5. [SPE] Subtract 117 on both sides:                                                                    2x² + 6x - 108 = 0
  6. Factor out GCF:                                                                                               2(x² + 3x - 54) = 0
  7. [DPE] Divide 2 on both sides:                                                                         x² + 3x - 54 = 0
  8. Factor Quadratic:                                                                                            (x - 6)(x + 9) = 0
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Since we are dealing with positive values, we can disregard the negative root.

∴ x = 6

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