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4 years ago

How to plot numbers in a number line

Mathematics

2 answers:

trasher [3.6K]4 years ago

8 0

There should be numbers using it you can plot the number you want on the number line

ahrayia [7]4 years ago

4 0

You draw a straight line and then put your number on the line. If you have to find a negative number, you can just go below zero. Positive numbers on a number line are always above zero. Hope this helps!

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What is the answer to this equation 3 + 3/2x + 4 = 4x - 5/2x

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Answer:

No solution

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When we take the 5/2 x to the other side, 4x and 4x cancels out. We get 7=0 which is incorrect. Therefore, x has no solution.

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Which statement explains if a dilation was applied? A dilation was applied to the fabric because the width of the fabric was pre

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Answer: A dilation was applied to the fabric because the angle measures were preserved.

Step-by-step explanation:

A dilation is a transformation that creates an image that is the exactly same shape as the original but have a different size.
It preserves the angles of the figure.
It does not preserve the side length of the figure.

Let's check the given statement:

If any side-length of the fabric was preserved then it's not dilation, so first statement is wrong.

By the definition of dilation, it preserves the angles of the figure so the second statement is correct.

Also, third and fourth statements are wrong by the definition of dilation.

Hence, the correct answer is " A dilation was applied to the fabric because the angle measures were preserved.".

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3 years ago

Determine whether each equation is True or False. In case you find a "False" equation, explain why is False.

elixir [45]

Answer:

(1) TRUE.

(2) FALSE.

(3) FALSE.

(4) TRUE.

(5) FALSE.

Step-by-step explanation:

(1) $\sqrt{32} = 2^{\frac{5}{2} }$

$2^{\frac{5}{2} } = (\sqrt{2} )^5 = (\sqrt{2} \ \times \ \sqrt{2} \ \times \ \sqrt{2} \ \times \ \sqrt{2} \ \times \ \sqrt{2}) = 4\sqrt{2}\\\\\sqrt{32} = \sqrt{16 \ \times \ 2}\ = \ \sqrt{16} \ \times \ \sqrt{2} \ = \ 4\sqrt{2}$

Thus, the equation is TRUE.

(2) $16^{\frac{3}{8} } = 8^2$

$16^{\frac{3}{8} } =(2^4)^{\frac{3}{8} } = 2^\frac{3}{2} }= (\sqrt{2} )^3 = (\sqrt{2} \ \times \ \sqrt{2} \ \times \ \sqrt{2}) = 2\sqrt{2} \\\\8^2 = 64$

Thus, the equation is FALSE.

(3) $4^{\frac{1}{2} } = \sqrt[4]{64}$

$4^{\frac{1}{2} }= \sqrt{4} = 2\\\\\sqrt[4]{64} = (64)^{\frac{1}{4} } = (2^6)^{\frac{1}{4} }= 2^{\frac{6}{4} } = 2^{\frac{3}{2} }=(\sqrt{2} )^3 = (\sqrt{2} \times \sqrt{2} \times \sqrt{2} ) = 2\sqrt{2}$

Thus, the equation is FALSE.

(4) $2^8 = (\sqrt[3]{16} )^6$

$2^8 = 256\\\\ (\sqrt[3]{16} )^6 = (16)^{\frac{6}{3} } = (2^4)^{\frac{6}{3} } = (2)^{\frac{24}{3} } = 2^8 = 256$

Thus, the equation is TRUE.

(5) $(\sqrt{64} )^{\frac{1}{3} } = 8^{\frac{1}{6} }\\\\$

$8^{\frac{1}{6} } = (2^3)^{\frac{1}{6} } = 2^{\frac{3}{6} } = 2^{\frac{1}{2} } = \sqrt{2} \\\\(\sqrt{64} )^{\frac{1}{3} } = (2^6)^{\frac{1}{3} } = 2^{\frac{6}{3} } = 2^2 = 4$

Thus, the equation is FALSE.

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3 years ago