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emmainna [20.7K]
4 years ago
7

Write the statement for each of the following expressions (x+3)×4

Mathematics
2 answers:
Yuki888 [10]4 years ago
7 0

Answer:

4x + 12

Step-by-step explanation:

(x+3)×4

(x×4) + (3×4)

4x + 12

USPshnik [31]4 years ago
3 0

Answer:

4x + 12

Step-by-step explanation:

(x+3)×4

(x×4) + (3×4)

4x + 12

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39x38 multiply using partial prodcuts
yKpoI14uk [10]
39 x 10
= 390

39 x 40 (390 x 4)
= 1,560

39 x 2
= 78

1,560 - 78
= 1,482

ANSWER: 1,482
4 0
3 years ago
A) Write an expression for the slope of the secant line through the points
Crazy boy [7]

Answer:

Step-by-step explanation:a/

slope m = [f(x)-f(3)]/(x-3)

b/

tangent y - f(3) = [lim m ,as x-->3](x-3)

7 0
3 years ago
Brian tied a 136-foot rope around the perimeter of his rectangular house. He knows that the length of the house is 10 feet less
STALIN [3.7K]

Answer:

length 42 cm and width 26 cm

Step-by-step explanation:

Given

Since Brian tied 136 foot rope around the perimeter , hence perimeter of house is 136 foot.

Given that shape of house is rectangular.

formula to calculate perimeter of rectangle can be used which is 2*(L+B)

where L is length of rectangle and B width of rectangle

Let the L and B be length of rectangular side of house

According to question

length of house is 10 feet less than twice the width of house

mathematically it can be represented as

L = 2*B - 10  --->eq. 1

Perimeter of house = 136 feet

using formula of Perimeter of rectangle

136 = 2*(L+B)

substituting the value of length in terms of width from eq. 1 in formula of perimeter

=> 136/2 = 2*B - 10 + B  (2*B+ B = 3B)

=> 68 = 3*B - 10

=> 78 = 3*B

B = 78/3 = 26

Therefore B which is width = 26 CM

length = 2*B - 10= 26*2 - 10 = 52-10=42

length of house = 42  cm

Hence dimension of Brian's house is length 42 cm and width 26 cm

5 0
3 years ago
Given that f(x) = 19x2 + 152, solve the equation f(x) = 0
telo118 [61]

<em><u>Option A</u></em>

<em><u>The solution is:</u></em>

x = \pm 2i \sqrt{2}

<em><u>Solution:</u></em>

f(x) = 19x^2+152

We have to solve the equation f(x) = 0

Let f(x) = 0

0=19x^2+152

Solve the above equation

19x^2 + 152 = 0

\mathrm{Subtract\:}152\mathrm{\:from\:both\:sides}\\\\19x^2+152-152=0-152\\\\Simplify\ the\ above\ equation\\\\19x^2 = -152\\\\\mathrm{Divide\:both\:sides\:by\:}19\\\\\frac{19x^2}{19} = \frac{-152}{19}\\\\x^2 = -8

Take square root on both sides

x =  \pm \sqrt{-8}\\\\x = \pm \sqrt{-1}\sqrt{8}\\\\\mathrm{Apply\:imaginary\:number\:rule}:\quad \sqrt{-1}=i\\\\x = \pm i\sqrt{8}\\\\x = \pm i \sqrt{2 \times 2 \times 2}\\\\x = \pm 2i\sqrt{2}

Thus the solution is found

5 0
3 years ago
Please Subtract the Following Fractions.
vovangra [49]

¡Hola!

Your answer to the question is 10/12.

Step-by-step explanation:

By using the y^2-y^1/x^2-x^1

12-2= 10

16-4= 12

So your answer is 10/12.

Hope this Helps!

4 0
3 years ago
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