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4 years ago

15

PLZZZ HELP ME OUT THIS DUE RIGHT NOW AND I FREAKING OUT PLEASE HELP ME P.S YOU HAVE WRITE ANSWERS FOR ALL OF THEM

2 answers:

GenaCL600 [577]4 years ago

8 0

I- I’m confused my good sir/ma’am

Orlov [11]4 years ago

6 0

It really depends on what the variable represents (if it is a bigger number than the one near it it will be positive and if the number is a negative then he answer would be negative) or you could have just shown us the number line and we could have helped.

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PLEASE ANSWER QUICKLY I WILL GIVE 50 POINTS AND MARK AS BRAINLIEST

ASHA 777 [7]

hello there! your 2 answers are A. and E. I hope that you can find this of use to you! I also pray that your day is going wonderful!☻

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3 years ago

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Suppose this relation forms a function: {(3,-5), (-2,9), (0,4), (x,7)}. What values are not possible for the value of x?

kakasveta [241]

Since the definition of a function is that x values can’t repeat, any X values that are used in the other coordinates cannot be reused. So the answer has to be x cannot equal 3, -2, or 0

4 0

3 years ago

Find an equivalent function to f(x) = 5(3)^3x. (5 points)

Elena-2011 [213]

Answer:

$B. f(x) = 5(27)^x$

Step-by-step explanation:

Well lets graph it first,

Look at the image below ↓

By looking at the image we can tell that answer choice $B. f(x) = 5(27)^x$ .

<em>Thus,</em>

<em>answer choice B is correct.</em>

<em />

<em>Hope this helps :)</em>

3 0

3 years ago

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Find the volume of the composite solid. Round your answer to the nearest hundredth.

Vera_Pavlovna [14]

Answer: see my work

Step-by-step explanation:

volume is lwh

volume is 3*3*10

volume is 9*10

volume is cubic cm

volume is 90

volume is 90 cubic cm

8 0

2 years ago

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Measure the lengths of the sides of ∆ABC in GeoGebra, and compute the sine and the cosine of ∠A and ∠B. Verify your calculations

marusya05 [52]

Answer:

$Sin \angle A =0.80$

$Cos \angle A=0.60$

$Sin \angle B =0.60$

$Cos \angle B=0.80$

Step-by-step explanation:

Given

I will answer this question using the attached triangle

Solving (a): Sine and Cosine A

In trigonometry:

$Sin \theta =\frac{Opposite}{Hypotenuse}$ and

$Cos \theta =\frac{Adjacent}{Hypotenuse}$

So:

$Sin \angle A =\frac{BC}{BA}$

Substitute values for BC and BA

$Sin \angle A =\frac{8cm}{10cm}$

$Sin \angle A =\frac{8}{10}$

$Sin \angle A =0.80$

$Cos \angle A=\frac{AC}{BA}$

Substitute values for AC and BA

$Cos \angle A=\frac{6cm}{10cm}$

$Cos \angle A=\frac{6}{10}$

$Cos \angle A=0.60$

Solving (b): Sine and Cosine B

In trigonometry:

$Sin \theta =\frac{Opposite}{Hypotenuse}$ and

$Cos \theta =\frac{Adjacent}{Hypotenuse}$

So:

$Sin \angle B =\frac{AC}{BA}$

Substitute values for AC and BA

$Sin \angle B =\frac{6cm}{10cm}$

$Sin \angle B =\frac{6}{10}$

$Sin \angle B =0.60$

$Cos \angle B=\frac{BC}{BA}$

Substitute values for BC and BA

$Cos \angle B=\frac{8cm}{10cm}$

$Cos \angle B=\frac{8}{10}$

$Cos \angle B=0.80$

Using a calculator:

$A = 53^{\circ}$

So:

$Sin(53^{\circ}) =0.7986$

$Sin(53^{\circ}) =0.80$ -- approximated

$Cos(53^{\circ}) = 0.6018$

$Cos(53^{\circ}) = 0.60$ -- approximated

$B = 37^{\circ}$

So:

$Sin(37^{\circ}) = 0.6018$

$Sin(37^{\circ}) = 0.60$ --- approximated

$Cos(37^{\circ}) = 0.7986$

$Cos(37^{\circ}) = 0.80$ --- approximated

8 0

3 years ago

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