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dangina [55]
3 years ago
8

Find the minimum cost of producing 60000 units of a product, where x is the number of units of labor, at $99 per unit, and y is

the number of units of capital expended, at $84 per unit. And determine how many units of labor and how many units of capital a company should use. Where the production level is given by P(x, y) = 100x^0.25 y^0.75
Mathematics
1 answer:
Y_Kistochka [10]3 years ago
3 0

Answer:

The minimum cost of producing 60000 units of a product is $105867

Step-by-step explanation:

Since x is the number of units of labor, at $99 per unit, and y is the number of units of capital expended, at $84 per unit, The cost C(x,y) is given by:

C(x, y) = 99x + 84y

P(x, y) = 100x^{0.25}y^{0.75}

For the minimum cost:

100x^{0.25}y^{0.75}=60000\\x^{0.25}(\frac{33x}{28} )^{0.75}=600\\x^{0.25}(\frac{33}{28} )^{0.75}x^{0.75}=600\\x^{0.25+0.75}*1.131=600

Using the langrage multiplier,

99=0.25(100)x^{-0.75}y^{0.75}\lambda...(1\\84=0.25(100)x^{0.25}y^{-0.25}\lambda...(2

Dividing both equation 1 and 2

y=\frac{33}{28}x

Substituting y=\frac{33}{28}x in 100x^{0.25}y^{0.75}=60000, we get:

x_{min}=530.44 labor units

Substituting x_{min}=530.44  labor units in y=\frac{33}{28}x, we get

y_{min}=\frac{33}{28}*530.44=625.16 labor unit

C(x, y) = 99x + 84y=99(530.44)+84(635.16) = $105867\\

The minimum cost of producing 60000 units of a product is $105867

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Mariulka [41]

The function values for the function f(x) = 3x² + 2x - 6, for the values are:

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<h3>How are function values calculated?</h3>

To calculate function value f(k) for a function f(x), we substitute variable x = k, in the function f(x).

<h3>How to solve the question?</h3>

In the question, we are asked to find the function value for the function f(x) = 3x² + 2x - 6 for:

a. f(0)

b. f(2)

c. f(-4)

d. f(b)

e. f(4a).

We calculate these in the following ways:-

a. f(0):

We substitute the value of x = 0 in the function f(x).

Therefore f(0) = 3(0)² + 2(0) - 6,

or, f(0) = 0 + 0 - 6 = -6.

Therefore, the function value f(0) for the function f(x) = 3x² + 2x - 6 is <u>-6</u>.

b. f(2):

We substitute the value of x = 2 in the function f(x).

Therefore f(2) = 3(2)² + 2(2) - 6,

or, f(2) = 12 + 4 - 6 = 10.

Therefore, the function value f(2) for the function f(x) = 3x² + 2x - 6 is <u>10</u>.

c. f(-4):

We substitute the value of x = -4 in the function f(x).

Therefore f(-4) = 3(-4)² + 2(-4) - 6,

or, f(-4) = 48 - 8 - 6 = 34.

Therefore, the function value f(-4) for the function f(x) = 3x² + 2x - 6 is <u>34</u>.

d. f(b):

We substitute the value of x = b in the function f(x).

Therefore f(b) = 3(b)² + 2(b) - 6,

or, f(b) = 3b² + 2b - 6.

Therefore, the function value f(b) for the function f(x) = 3x² + 2x - 6 is <u>3b² + 2b - 6</u>.

e. f(4a):

We substitute the value of x = 4a in the function f(x).

Therefore f(4a) = 3(4a)² + 2(4a) - 6,

or, f(0) = 48a² + 8a - 6.

Therefore, the function value f(0) for the function f(x) = 3x² + 2x - 6 is <u>48a² + 8a - 6</u>.

Learn more about finding function values at

brainly.com/question/27943419

#SPJ2

4 0
2 years ago
Read 2 more answers
CHECK MY ANSWER??
Tatiana [17]
You are partially correct :) 2^SQR(10) x SQR(10) = 20 
The answer is just 20
4 0
3 years ago
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