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3 years ago

(AAAASSSSSSAAAAPPPP!)

Mathematics

2 answers:

Ierofanga [76]3 years ago

5 0

C. 3+6x because your contributing the equation

Paul [167]3 years ago

3 0

The answer to this question is C.

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The perimeter of an equilateral triangle is 65 cm, to the nearest centimetre.

iogann1982 [59]

Answer:

The smallest possible side length is around 21.3.

Step-by-step explanation:

Equilateral triangles have 3 sides of equal lengths.

65 ÷ 3 = $\frac{65}{3}$ or 21.333

4 0

3 years ago

Read 2 more answers

What is the equation for the line with slope m=−4 and y-intercept b=3

andreev551 [17]

Answer:

ok so i am going to give you a litle saying to help you remember the way it goes ok. this problem is in slope-intercept form

"y=mx+b,,b is my y-intercept you'll see,m is my slope which is rise over run"

so if -4 is your slope it will go where the m is in the formula y=mx+b so it would now be y=-4x+b and then the b is your y-intercept so 3 would go where the b is in the formula now now since we plugged in all the parts.

<u>the answer is y=-4x+3 </u>

Step-by-step explanation:

5 0

3 years ago

Solve for x <br><img src="https://tex.z-dn.net/?f=4x%20-%2016%20%3D%200" id="TexFormula1" title="4x - 16 = 0" alt="4x - 16 = 0"

Shkiper50 [21]

Get x by itself
add 16 to both sides, so 4x = 16
divide both side by 4 and x =4

4 0

2 years ago

Read 2 more answers

Write each expression using exponents.<br> 3/8 * 3/8 * 3/8=

krok68 [10]

Answer:

3/8^3

Step-by-step explanation:

the exponent is 3

4 0

3 years ago

Read 2 more answers

Triangle ABC has vertices at A(-4, -2), B(1, 7) and C(8, -2)

Arada [10]

Answer:

a). Area = 54 square units

b). Perimeter = 33.7 units

Step-by-step explanation:

Vertices of the triangle ABC are A(-4, -2), B(1, 7) and C(8, -2).

(a). Area of the triangle ABC = $\frac{1}{2}[x_{1}(y_{2}-y_{3})+x_{2}(y_{3}-y_{1})+x_{3}(y_{1}-y_{2})]$ (Absolute value)

By substituting the values from the given vertices,

Area = $\frac{1}{2}[(-4)(7+2)+(1)(-2+2)+8(-2-7)]$

= $\frac{1}{2}[-36+0-72]$

= $\frac{1}{2}(-108)$

= (-54) unit²

Therefore, absolute value of the area = 54 square units

(b). Distance between two vertices (a, b) and (c, d)

d = $\sqrt{(a-c)^{2}+(b-d)^2}$

AB = $\sqrt{(-4-1)^{2}+(-2-7)^{2}}$

= $\sqrt{106}$

= 10.295 units

BC = $\sqrt{(1-8)^2+(7+2)^2}$

= $\sqrt{130}$

= 11.402 units

AC = $\sqrt{(-4-8)^2+(-2+2)^2}$

= 12 units

Perimeter of the triangle = AB + BC + AC = 10.295 + 11.402 + 12

= 33.697

≈ 33.7 units

7 0

3 years ago