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Andru [333]
3 years ago
13

There is a 25% chance that Dane will make a three-point shot during a basketball game. A random-number generator generated 10 se

ts of random numbers from 1 to 4. The number 3 represents Dane's making a three-point shot. Look at the table.​

Mathematics
1 answer:
Gelneren [198K]3 years ago
3 0

Answer:

the 25% chance is wrong, it is actually 20%

Step-by-step explanation:

Based on the table of trials shown in the picture, it seems that the 25% chance is wrong. In the table, there are 10 trials and each one has 5 numbers generated, meaning there are a total of 50 numbers generated. Out of these 50 numbers, only 10 are the number 3. Since 3 is the only number that represents a three-point shot, that would make it a 20% (10 / 50) chance that Dane makes a three-point shot in a basketball game.

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2 years ago
10. Create a scenario to explain why 3P3=3!.
Flauer [41]

Step-by-step explanation:

Permutation :The number of ways to choose a sample of r elements from a set of n distinct objects where order does matter and replacements are not allowed.

                                  nPr = \frac{n!}{(n-r)!}

Factorial : There are n! ways of arranging n distinct objects into an ordered sequence.  

Considering a situation when n = r in a permutation, nPr reduces to n!, a simple factorial of n.

Proof: 3P3 = 3!

n = 3 and r = 3

                                   3P3 = \frac{3!}{(3-3)!}

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But 0! = 1

                                    3P3 = 3!

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3 years ago
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Answer:

90

Step-by-step explanation:

= 6(12+3)

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Answer:

c\leq \$17

Step-by-step explanation:

Let

c -----> the additional amount (in dollars) David will spend

we know that

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The amount David has spent plus possible additional amounts he will spend must be less than or equal to $39

so

The inequality that represent this situation is

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solve for c

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c\leq 39-22

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The maximum amount he could spend is $17

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