By substitution is how to solve
2x-3y=21
y=3-x
2x-3(3-x)=21
2x-9+3x=21
5x=30
x= 6
now substitute our x value into y=3-x
so we get
y=3-6 = -3
so x=6 and y=-3 hope this helps!!!!! Thank you!
X^4 - x^2 + 9 - (x^3 + 3x^2 + 12) =
x^4 - x^3 - 4x^2 - 3
B. 0.930 ~Apex ;) .....................................
Answer is d. -5/3 because y2-y1 =x2-x1
