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Komok [63]
3 years ago
13

I’ll give you 15 point just help

Mathematics
1 answer:
Maru [420]3 years ago
4 0

Answer:

Step-by-step explanation:

y - 4 = -2/3(x - 3)

y - 4 = -2/3x + 2

y = -2/3x + 6

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Solve for v.<br> 3v=75<br> Simplify.
oee [108]

Answer: v = 25

Step-by-step explanation:

Divide each side by 3

3v/3 = v

75/3 = 25

v = 25

25 * 3 = 75

6 0
4 years ago
Read 2 more answers
PLZZZZ HELP MEEEE
Yuki888 [10]
X=3
r<span>≥8
n=6
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3 0
3 years ago
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Help me please
Fittoniya [83]
110a3b3c4 is yours answer.
8 0
2 years ago
Identifying Possible Triangles
Masja [62]

Answer:

3rd triangle can be constructed with dimensions 2,6,7.

Step-by-step explanation:

sum of any two sides > third side.

difference of any two sides < third side

1.

8+5=13 not >14 (no triangle.)

2.

7+8=15 not >15 (no triangle)

3.

2+6=8>7

2+7=9>6

7+6=13>2

7-2=5<6

7-6=1<2

6-2=4<7

so it is a triangle.

4.

6+3=9 not >10 (not a triangle)

5 0
3 years ago
A small combination lock on a suitcase has 55 ​wheels, each labeled with the 10 digits 0 to 9. How many 55 digit combinations ar
den301095 [7]
Suppose a_n is the number of possible combinations for a suitcase with a lock consisting of n wheels. If you added one more wheel onto the lock, there would only be 9 allowed possible digits you can use for the new wheel. This means the number of possible combinations for n+1 wheels, or a_{n+1} is given recursively by the formula

a_{n+1}=9a_n

starting with a_1=10 (because you can start the combination with any one of the ten available digits 0 through 9).

For example, if the combination for a 3-wheel lock is 282, then a 4-wheel lock can be any one of 2820, 2821, 2823, ..., 2829 (nine possibilities depending on the second-to-last digit).

By substitution, you have

a_{n+1}=9a_n=9^2a_{n-1}=9^3a_{n-2}=\cdots=9^na_1=10\times9^n

This means a lock with 55 wheels will have

a_{55}=10\times9^{54}

possible combinations (a number with 53 digits).
7 0
3 years ago
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