Let x be the volume (liters) of pure (at 100%) acid needed
Let y be the volume (liters) of the other acid (at 10%) needed
The final solution will be:
a) x+ y = 63 liters, AND their respective concentration in acid: is
100% x & 10% :y that will generate 63 liters at 20%
b) x +0.1 y = 63x 0.2 = 12.6
Let's solve this system of 2 equations:
x + y =63
x + 0.1 y = 12.6
Solving it will give you:
x= 7 liters at 100%
y = 56 liters at 10%
Answer:
y=4.2x-3.7
Step-by-step explanation:
Slope-intercept form is y=mx+b, so just plug in the numbers to where they go in the formula.
Answer:
if it's bot raining, then it's sunny
The first working out is correct, z = 3
<span>B. 16 quarts of the 2% milk and 24 quarts of the 7% milk
First, let's create an equation to solve.
x = quarts of 2% milk
(40-x) = quarts of 7% milk
So we have the equation
x*2 + (40-x)*7 = 40*5
Now to solve for x
x*2 + (40-x)*7 = 40*5
x*2 + 7*40 - 7*x = 40*5
x*2 - 7*x = 40*5 - 7*40
-5*x = - 2*40
x = 2*8
x = 16
So we need 16 quarts of 2% milk and 40-16 = 24 quarts of 7%, which matches option "B".</span>
