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3 years ago

Rainbow rainbow, high and bright.

Mathematics

1 answer:

slega [8]3 years ago

4 0

Answer:

is this a song or something

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A student concluded that the solution to the equation sqrt2x+1 +3=0 is x=4. Do you agree? Why or why not?

Katyanochek1 [597]

Just put 4 as x in the equation and solve it. The new equation is:

sqrt(2*4)+1+3 = 0

Now we can solve it.

sqrt(2*4) becomes sqrt8:

sqrt8+1+3=0. -------> sqrt8+4=0

The sqrt of 8 is about 2.83.. so 2.83+4 is:

6.83

So we have 6.83 as the answer

but 6.83 does not equal 0 so x cannot equal 4

5 0

2 years ago

What is a y-intercept of the continuous function in the table?

Vadim26 [7]

Answer:

5=y-intercept

Step-by-step explanation:

the y intercept point is when y has a number but x is 0 so we see what is y (f(x)) and it is 5

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2 years ago

Which substances dissolve in water? Check all of

Arturiano [62]

Answer:

polar liquids and polar solids

Step-by-step explanation:

6 0

3 years ago

Read 2 more answers

Rachel has 90p. Simon has £2.

natulia [17]

Answer:

9:20 is the answers for the question

Step-by-step explanation:

please tell me your

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2 years ago

Read 2 more answers

How do you solve it?

MatroZZZ [7]

Answer:

i: x=-2, x=1

ii: x=-1/2

Step-by-step explanation:

Quadratic form:

You solve i by using FOIL (First, Outside, Inside, Last) because it is a multiplication problem.

$(x+2)(x-1)=0$

"first" would be $x*x$ , which would equal $x^{2}$

"outside" would be $x*-1$ , which would equal $-1x, or -x$

"inside" would be $2*x$ , which would equal $2x$

"last" would be $2*-1$ , which would equal $-2$

Now you need to combine the terms so that they are one after the other

$x^{2}-x$ $+2x-2$

Combine like terms, and you should get:

$x^{2} +x-2$

i Solution

You need to get the variable by itself.

Subtract two from both sides

$x+2=0\\x=-2$

Add one to both sides.

$x-1=0\\x=1$

ii Solution

Add all the terms.

$x+2+x-1=0\\2x+1=0\\2x=-1\\x=-\frac{1}{2}$

8 0

3 years ago