15y + 31 = 61
15y = 61 - 31
15y = 30
y = 30 ÷ 15
<u>y = 2</u>
Answer:
Top right
Step-by-step explanation:
Rise/run is useful in this situation also is this iready?!
The image of the arrow is missing, so i have attached it.
Answer:
A_t = 69.5 cm²
Step-by-step explanation:
In a second image attached, I have divided the arrow into triangle and rectangle.
From the second image,
A1 is area of triangle while A2 is area of rectangle
Area of triangle is; A1 = ½bh
Our triangle base is given as 9 cm.
To get the height, we will subtract the rectangle height of 8 cm from the total arrow height.
Thus; height of triangle; h = 11 - 8 = 3cm
Thus;
A1 = ½ × 9 × 3
A1 = 13.5 cm²
Formula for area of rectangle is;
A2 = length × breadth
A2 = 8 × 7
A2 = 56 cm²
Thus, total area of arrow is;
A_t = A1 + A2 = 13.5 + 56
A_t = 69.5 cm²
He can give at most 2 adult haircuts with the remaining time
<h3>How many adult haircuts at most can he give with the remaining time? </h3>
The inequality is given as:
0.75C + 1.25A <= 7
Also, we have
C = 5
Substitute C = 5 in 0.75C + 1.25A <= 7
0.75 * 5 + 1.25A <= 7
Evaluate the product
3.75 + 1.25A <= 7
Evaluate the like terms
1.25A <= 3.25
Divide by 1.25
A <= 2.6
Rewrite as
A < 3
Hence, he can give at most 2 adult haircuts with the remaining time
Read more about inequalities at:
brainly.com/question/15010638
#SPJ1
<u>Complete question</u>
Horace is a professional hair stylist. Let C represent the number of child haircuts and A represent the number of adult haircuts that Horace can give within 7 hours. 0.75C + 1.25A <= 7
Horace gave 5 child haircuts.
How many adult haircuts at most can he give with the remaining time?
$250+$100__350. $1.50+$4.00___5.50
