If the perimeter of the equilateral triangle is 18 cm then the width of the rectangle be 11.2 cm.
Given that the perimeter of the equilateral triangle be 18 cm and the perimeter of all the three triangles be 46.4 cm.
We are required to find the width of the rectangle.
Rectangle is basically the shape which is having opposite sides equal to each other.
Perimeter of equilateral triangle=3 *side
3* side=18
side=18/3
side=6
Since it is on the length of the rectangle so the length of rectangle be
6 cm.
Perimeter of all the three triangles=2*width of the rectangle+1 length+perimeter of 1 equilateral triangle.
T1 and T2 are the other triangles.
Suppose the width of the rectangle be x.
Perimeter=2*x+6+18
46.4=2x+24
2x=46.4-24
2x=22.4
x=11.2
So,the width of the rectangle is equal to 11.2 cm.
Hence if the perimeter of the equilateral triangle is 18 cm then the width of the rectangle be 11.2 cm.
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Answer:
2.5
Step-by-step explanation:
It's because 1is less than 5
If you move the decimal from left to right, then you make it either a whole number or a percentage.
Answer:
r = 3.
Step-by-step explanation:
16 = 10 + √(3r + 27)
√(3r + 27) = 6
Square both sides:
3r + 27 = 36
3r = 36 - 27 = 9
r = 3.
Check the result:
Left side of the equation = 16
Right side = 10 + √(9 + 27)
= 10 + √36 = 16
Answer:
5cm
Step-by-step explanation:
Given area of trapezium = 31.5 sq. cm
Length of parallel sides = 7.3cm and 5.3cm
Formula to calculate area of trapezium is
1/2*(sum of parallel sides)*perpendicular distance between parallel sides
sum of parallel sides = (7.3 + 5.3) = 12.6cm
substituting value of area given and sum of parallel sides we have
31.5 = 1/2* 12.6 * perpendicular distance between parallel sides
(31.5 * 2)/12.6 = perpendicular distance between parallel sides
perpendicular distance between parallel sides = 63/12.6 = 5
Therefore perpendicular distance between parallel sides for given trapezium is 5cm.
