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Veseljchak [2.6K]
3 years ago
8

A taxi charges a fee, plus $1.80 per mile. how far can you go for $12?

Mathematics
1 answer:
EleoNora [17]3 years ago
7 0

12: 1.8= 20/3. =>  the answer is 20/3 miles

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You are choosing between two different cell phone plans. The first plan charges a rate of 24 cents per minute. The second plan c
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Answer: 286 minutes

Step-by-step explanation:

x : # of months that has gone by

0.24x : cost of the 24 cent plan after "x" minutes

39.95 + 0.10x : cost of the 10 cent plan after "x" minutes

1. 39.95 + 0.10x > 0.24x

2. 39.95 > 0.24x - 0.10x

3. 39.95 > 0.14x

4. 285.36 > x

x must be AT LEAST 286 minutes for plan #2 (39.95 + 0.10x) to be a better deal

7 0
2 years ago
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A is the midpoint of BC. <br> BA = 3x+8 <br> AC=23. <br> solve for x
AnnyKZ [126]

Since A is the midpoint of BC, we can assume BA and AC are equal to each other.

We also know that BC = BA + AC = 23 + 23 = 46

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3 years ago
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Geometry proof<br> help please
Aleks [24]
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Is x+y+1=0 a tangent of both y^2=4x and x^2=4y parabolas?
Lubov Fominskaja [6]

Answer:

  yes

Step-by-step explanation:

The line intersects each parabola in one point, so is tangent to both.

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For the first parabola, the point of intersection is ...

  y^2 = 4(-y-1)

  y^2 +4y +4 = 0

  (y+2)^2 = 0

  y = -2 . . . . . . . . one solution only

  x = -(-2)-1 = 1

The point of intersection is (1, -2).

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For the second parabola, the equation is the same, but with x and y interchanged:

  x^2 = 4(-x-1)

  (x +2)^2 = 0

  x = -2, y = 1 . . . . . one point of intersection only

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If the line is not parallel to the axis of symmetry, it is tangent if there is only one point of intersection. Here the line x+y+1=0 is tangent to both y^2=4x and x^2=4y.

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Another way to consider this is to look at the two parabolas as mirror images of each other across the line y=x. The given line is perpendicular to that line of reflection, so if it is tangent to one parabola, it is tangent to both.

7 0
3 years ago
enrollment in the ski/snowboard club increased by 30% this year. there are now 182 students in the club. how many students were
eduard
Enrolement increased by 30% that means last year=100%
incease of 30%=30+100=130% now

now=182

percent means parts out of 100 so
130%=130/100=13/10


182=13/10 of x (x represents the number last year)
of means multipy so
182=13/10 times x
multiply both sides by 10/13 to clear fraction
182 times 10/13=x=140



140 students last year
8 0
3 years ago
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